Answer:
m∠ADC = 90°
Step-by-step explanation:
Since, AB║CD and side AD is a transverse intersecting these parallel lines,
m∠DAC + m∠ADC = 180° [Consecutive interior angles]
85° + m∠ADC = 180°
m∠ADC = 180 - 85
= 95°
Therefore, measure of angle ADC = 95° will be the answer.
<em>3x - y = 5</em>
- Step-by-step explanation:
<em>2x + y = 10 | ×2</em>
<em>x - 2y = -5</em>
<em />
<em>4x + 2y = 20</em>
<em>x - 2y = -5</em>
<em>add</em>
<em>4x + x + 2y - 2y = 20 - 5</em>
<em>5x = 15</em>
<em>x = 15 : 5</em>
<em>x = 3</em>
<em>replace x</em>
<em>4(3) + 2y = 20</em>
<em>12 + 2y = 20</em>
<em>2y = 8</em>
<em>y = 8 : 2</em>
<em>y = 4</em>
3x - y =
= 3(3) - 4
= 9 - 4
= 5
One ratio is 30:40 since 15 times 2 is 30 and 20 times 2 is 40.
Hope it can solve you problem... :)
