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2 years ago

10

Name all sets of numbers to which each real number belongs

1 answer:

Ivahew [28]2 years ago

6 0

Real Number
Whole Numbers:0,1,2,3,4,5,6,7,8,9,10,etc.
Counting Numbers:1,2,3,4,5,6,7,8,etc.
Natural Numbers:which is whole or counting numbers depends on the topic
Integers:-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7,8,9,10,etc.

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Can you please help me answer this

lesya692 [45]

9514 1404 393

Answer:

(a) Not congruent

Step-by-step explanation:

Angles are congruent, which means the triangles are <em>similar</em>. We need to know at least one pair of corresponding sides is congruent in order to say the triangles are congruent. No sides are marked, so we must conclude ...

Not Congruent

8 0

2 years ago

A population of rabbits on a farm grows by 12% each year. Assume that this increase occurs as new baby rabbits at the beginning

jolli1 [7]

Answer:

a) r₁₂ = 104.36

In general, rₙ = arⁿ⁻¹

b)

- rabbit food consumed during the 10th year is approximately 832 pounds

- rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds

Step-by-step explanation:

Given that:

r1 = 30 and a farm grows by 12%

a = 30 and the common ratio r = 1.12

now

n r

1 30.00

2 33.60

3 37.63

4 42.15

5 47.21

6 52.87

7 59.21

8 66.32

9 74.28

10 83.19

11 93.18

12 104.36

Therefore r₁₂ = 104.36

In general, rₙ = arⁿ⁻¹

b)

if each rabbit consume 10 lbs of rabbit food each year

n r food consumed(lbs)

1 30.00 300

2 33.60 336

3 37.63 376

4 42.15 422

5 47.21 472

6 52.87 529

7 59.21 592

8 66.32 663

9 74.28 743

10 83.19 832

total 5265

Therefore, the rabbit food consumed during the 10th year is approximately 832 pounds

And the rabbit food consumed in total for the 1st through 10th years is approximately 5265 pounds

6 0

1 year ago

Solve the equation for x 2/3 x -1/9x+5=20

Usimov [2.4K]

Answer: X = 45

This may help.

6 0

2 years ago

Read 2 more answers

Help me pls!!!!!!!!!

Dominik [7]

Answer:

$x^2+18=-9x : x = -3, x = -6$

Step-by-step explanation:

$x^2+18=-9x$

Add 9x to both sides:

$x^2+18+9x=-9x+9x$

Simplify:

$x^2+9x+18=0$

Solve with the quadratic formula:

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are:

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

For $a=1,\:b=9,\:c=18:\quad x_{1,\:2}=\frac{-9\pm \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1}$

$x =\frac{-9 + \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -3$

$x =\frac{-9 - \sqrt{9^2-4\cdot \:1\cdot \:18}}{2\cdot \:1} : -6$

The solution to the quadratic equation are:

$x=-3,\:x=-6$

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day!

6 0

2 years ago

For each table of values, write an expression that relates the input to the output.

Arlecino [84]

Answer:

x3, +3

Step-by-step explanation:

Each number gets multiplied by 3 and then you add 3.

8 0

1 year ago