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lara [203]
3 years ago
8

Help me please will give points

Mathematics
1 answer:
ehidna [41]3 years ago
7 0
Answer: 675

m represents the time she has been paying. And B represents how much she owed.
So to find how much she owed at the beginning, when no time had passed, we need to set m equal to zero.

When m is zero, the equation is
B = -100(0) + 675
B= 675

So 675 is how much she owed at the beginning of the year.
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Help me plz I don’t understand step by step explanation will help
Grace [21]

Answer:

m∠2 = 40°

Step-by-step explanation:

Because the 2 lines are parallel, that means ∠1 and ∠2 are corresponding angles. Using the Corresponding Angles Theorem, m∠1 = m∠2. Therefore, m∠2 is 40°.

5 0
3 years ago
I had to rewrite the questions cause I don't know how to edit them on a computer and PLEASE ANSWER but here is the question:
Ipatiy [6.2K]

Answer

v=13

Step-by-step explanation:

110/9 = v

Round up.

8 0
2 years ago
i have the same hundreds digit as ones digit the value of my tens digit is 50 the value of my ones digit is 4 what is my 3 digit
Iteru [2.4K]
The answer is 454 I hope I helped
4 0
3 years ago
Read 2 more answers
1. Find the phase shift of the function y = 5cos(2x + pi/2).
kolezko [41]

Answer:

see explanation

Step-by-step explanation:

1

The cosine function in standard form is

y = acos(bx + c)

where a is the amplitude, period = \frac{2\pi }{b} and

phase shift = - \frac{c}{b}

here b = 2 and c = \frac{\pi }{2}, thus

phase shift = - \frac{\frac{\pi }{2} }{2} = - \frac{\pi }{4}

2

the amplitude = | a |

which has a maximum of a and a minimum of - a

y = 4cosx ← has a maximum value of 4

5 0
3 years ago
You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confide
FrozenT [24]

Question:

You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of ​$114.00. Assume the population standard deviation is ​$15.30. Construct a​ 90% confidence interval for the population mean.

Answer:

At the 90% confidence level, confidence interval = 110.2484 < μ < 117.7516

At the 95% confidence level, confidence interval = 109.53 < μ < 118.48

The 95% confidence interval is wider

Step-by-step explanation:

Here, we have

Sample size, n = 45

Sample mean, \bar x = $114.00

Population standard deviation, σ = $15.30

The formula for Confidence Interval, CI is given by the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where, z is found for the 90% confidence level as ±1.645

Plugging in the values, we have;

CI=114\pm 1.645 \times \frac{15.3}{\sqrt{45}}

or CI: 110.2484 < μ < 117.7516

At 95% confidence level, we have our z value given as z = ±1.96

From which we have CI=114\pm 1.96 \times \frac{15.3}{\sqrt{45}}

Hence CI: 109.53 < μ < 118.48

To find the wider interval, we subtract their minimum from the maximum as follows;

90% Confidence level: 117.7516 - 110.2484 = 7.5

95% Confidence level: 118.47503 - 109.5297 = 8.94

Therefore, the 95% confidence interval is wider.

8 0
3 years ago
Read 2 more answers
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