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lukranit [14]
4 years ago
12

Y = 2x + 3 X Y -3 -1 2 4 5

Mathematics
2 answers:
antoniya [11.8K]4 years ago
4 0
Y = 2x + 3 \\  \\ x=-3 \\ Y = 2(-3) + 3=-6+3=-3\\  \\ x=-1 \\ Y = 2(-1) + 3=-2+3=1\\  \\ x=2 \\ Y = 2(2) + 3=4+3=7\\  \\ x=4 \\ Y = 2(4) + 3=8+3=11\\  \\ x=5 \\ Y = 2(5) + 3=10+3=13
Strike441 [17]4 years ago
3 0
Y=2x+3
for x = -3 y = 2*(-3)+3=-6+3=-3
for x = -1 y = 2*(-1)+3=-2+3=1
for x = 2 y = 2*2+3 = 4+3 = 7
for x = 4 y = 2*4+3 = 8+3 =11
for x = 5 y = 2*5+3 = 10+3 =13
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If I lost 4% of 100 pencils an 6% of 200 pens how many pencils do I have left and how many pens do I have left?
DedPeter [7]
To find 4% you multiply 100 by .04
100•.04=4
Then subtract
100-4=96 *you have 96 pencils left*

To find 6% of 200, multiply 200 by .06
200•.06=12
Then subtract
200-12=188 *you have 188 pens left*
6 0
3 years ago
Select all the correct answers.
andreev551 [17]

Answer: i believe the answers are A and C

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact
Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable  on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that  limit property of an  integral

\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt

\int_{a}^{b} fdt=f(b)-f(a)....(Equation I)

Using above property of integral then we get

\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt......(Equation II)

Substitute equation I and equation II are equal

Then we get

\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}

\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)

\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)

Therefore, \int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt.

Hence, the value of function does not change after changing the value of function at c.

6 0
3 years ago
One-eighth of a number is -4,200.
FinnZ [79.3K]

Answer:

33,600

Step-by-step explanation:

take -4200 and multiply it by 8. You'd do this since the equation to get -4200 is

x(1/8) = -4200

multiply both sides by 8 to get rid of the fraction and you get x=33,600

7 0
3 years ago
What is the quotient of these complex numbers?<br><br> (8-6i)/(3-i)
Aleks04 [339]

Answer: z = 6i / (4+3i)

Step-by-step explanation: Rectangular form:

z = 0.72+0.96i

Angle notation (phasor):

z = 1.2 ∠ 53°7'48″

Polar form:

z = 1.2 × (cos 53°7'48″ + i sin 53°7'48″)

Exponential form:

z = 1.2 × ei 0.2951672

Polar coordinates:

r = |z| = 1.2  magnitude (modulus, absolute value)

θ = arg z = 53.1301° = 53°7'48″ = 0.2951672π  angle (argument or phase)

Cartesian coordinates:

Cartesian form of imaginary number: z = 0.72+0.96i

Real part: x = Re z = 0.72

Imaginary part: y = Im z = 0.96

Hope this helps!

I am joyous to assist you anytime.

~Jarvis

3 0
3 years ago
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