All categories

3 years ago

Write the equation of the line that passed through the points (-1,6) and (5,0)

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

Answer: y = -1x + 5

Step-by-step explanation:

1. Plug the coordinates into the slope formula (y2 - y1)/ (x2 - x1)

(0 - 6)/ (5 -(-1))

2. Solve for slope

-6/6

= -1

3. Plug the first coordinate and slope into the point slope form equation (y - y1) = slope(x - x1) to find the rest of the equation of the line

(y -(-1)) = -1( x - 6)

4. Solve for y

y + 1 = -1x + 6 -----> y = -1x + 5

You might be interested in

Find the slope-intercept form of the equation of the line passing through the points.

LekaFEV [45]

Plog in to y=ax+b and u will find a b

5 0

3 years ago

Taylor earned $48 for 6 hours of babysitting and $68 for 8.5 hours of babysitting. How long would she have to babysit to earn $3

ZanzabumX [31]

48÷6=$8 per hour
So
32÷8=4 hours

6 0

3 years ago

The value of the fraction 3c+2/4 one less than the value of the fraction 5c-1/3.

Viefleur [7K]

Answer:

7/8 > 5/6

Step-by-step explanation:

A) 7/8

We can compare this as follows.

Lets say both are equal.

Cross multiplying these we get 40=42

We get 40<42. In fraction we get

In case if you want to convert this to decimal, we get;

5/6 = 0.833 and 7/8 = 0.875

We get 5/6<7/8

B) 4/5

Similarly we get 4/5 = 0.8 and 5/6 = 0.833

Here 4/5<5/6

C) 3/4

we get 3/4 = 0.75 and 5/6 = 0.833

3/4<5/6

D) 2/3

we get 2/3 = 0.66 and 5/6 = 0.833

2/3<5/6

Step-by-step explanation:

5 0

3 years ago

A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta

nalin [4]

Answer:

Option 2 - Approximately 24–36 pounds

Step-by-step explanation:

Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.

To find : What range of weights would 99.7% of the dogs have?

Solution :

The range of 99.7% will lie between the mean ± 3 standard deviations.

We have given,

Mean weight of Eskimo dogs is $\mu=30$

Standard deviation of Eskimo dogs is $\sigma=2$

The range of weights would 99.7% of the dogs have,

$R=\mu\pm3\sigma$

$R=30\pm3(2)$

$R=30\pm6$

$R=30+6,30-6$

$R=36,24$

Therefore, The range is approximately, 24 - 36 pounds.

So, Option 2 is correct.

5 0

4 years ago

K^2+5k-6=0 quadratic formula

s2008m [1.1K]

I hope this helps you

1.k^2+5k-6=0

a=1

b=5

c= -6

disctirminant =b^2-4ac

disctirminant =5^2-4.1. (-6)

disctirminant =49

x1= -(5)+ square root of 49/2.1

x1=-5+7/2

x1=1

x2= -5- square root of 49/2.1

x2= -5-7/2

x2= -6

7 0

3 years ago