Answer: i guess the problem is with P(x) => "x =
", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and
= 0. So p(0) is true.
b) x = 1 and
= 1, so P(1) is true.
c) x = 2, and
= 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and
= 1, and 1 ≠ -1, so P(-1) is false.
Answer: The graph crosses the x-axis at x = 2.
Step-by-step explanation:
The root has a multiplicity of 3, meaning that it crosses the x axis at x=2.
Both trees would be the same in 2 years at 7 feet.
Hope this helps.
Number 8? I don't know which one you are talking about.
Answer:
2 7/8
Step-by-step explanation:
first step is making these into improper fractions for example 6 1/8 would equal 49/8 because 6*8=48 and add the 1/8 to get 49/8 then do the same with the 3 1/4 make them into 8ths. so it would be 3 2/8 then 26/8 now subtract 49-26 to get 23/8. now simplify to get 2 7/8