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Aneli [31]
3 years ago
14

Anna is making soft toys she can sell at the fair. She can make 3 soft toys in 5 hours. How many soft toys can she make in 20 ho

urs?
A. 10

B. 12

C. 16

D. 20
Mathematics
2 answers:
svetoff [14.1K]3 years ago
6 0
The answer is B.12 because if she make 3 in 5 hours that means that in twenty hours should make 12 because it's like this 3 x 4 = 12 and 5 x 4 = 20 so when you add the hours up you'll get the answer
Dennis_Churaev [7]3 years ago
6 0

Answer:

B.12

Step-by-step explanation:

We can calculate it with a direct rule of 3. If in 5 hours she can make 3 soft toys, how many soft toys will she make in 20 hours?

\text{5 hours} -\!\!\!-\!\!\!- \text{3 soft toys}\\ \text{20 hours} -\!\!\!-\!\!\!- \text{x soft toys}

We use the formula of the direct rule of 3:

x = \frac {20*3}{5} \\ \\ x = \frac {60}{5}\\

x = 12

She can make 12 soft toys in 20 hours.

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Amanda says that a human fingernails has a thickness of about 4.2 x 10^-4 meter. Justin says that a human fingernails has a thic
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Answer:

See below

Step-by-step explanation:

1. Standard notation

4.2 × 10⁻⁴ m

A negative exponent indicates

  • A number between 0 and 1.
  • That the decimal point is shifted that number of places to the left.

4.2 × 10⁻⁴ tells you that the decimal number is 4.2, with the decimal point moved four places to the left.

The number becomes 0.000 42 .

2. Metres to millimetres

4.2 \times 10^{-4}\text{ m} \times \dfrac{10^{3}\text{ mm}}{\text{1 m}} = 4.2\times 10^{-1}\text{ mm = 0.42 mm}}

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Yes, because both measurements are the same as 0.42 m.

4. More appropriate measurement

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The given data can be completed in a tabular form by using the given data

points row and column totals.

Responses:

  • Part A: The percentage of the respondents that do not like both hamburgers and burritos is approximately 26.34%
  • Part B: The marginal relative frequency is approximately 0.537
  • Part C: The data point that has strongest association of its two factors is the data point for the respondents that like hamburger but do not like burritos which is 81

<h3>Methods used for the calculations:</h3>

The given data is presented as follows;

\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers& Total\\Likes burritos&29&41&\\Does not like burritos &&54&135\\Total&110&&205\end{array}\right]

Number of respondents that do not like burritos = 135 - 54 = 81

The total number of respondents that do not like hamburgers = 41 + 54 = 95

The total number of respondents that like burritos = 29 + 41 = 70

Part A:

Number of respondents that do not like both hamburgers and burritos = 54

The percentage of the survey that do not like both hamburgers and burritos (H∩B)' is therefore;

Percentage \ of \ (H \cap B)' =  \mathbf{\dfrac{54}{205} \times 100} = 26.\overline{34146} \ \% \approx  26.34 \ \%

  • The percentage that do not like both hamburgers and burritos is approximately <u>26.34%</u>

Part B:

Marginal relative frequency of all customers that like hamburgers.

Marginal \ relative \ frequency = \mathbf{\dfrac{Total \ number \ of \ customers \ that \ like \ hamburgers}{Grand \ total \ of \ repondents \ in \ the \ survey}}

Therefore;

  • Marginal \ relative \ frequency = \dfrac{110}{205} = \dfrac{22}{41} \approx \underline{ 0.537}

Part C:

The completed table is presented as follows;

\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers&Total\\Likes burritos&29&41&70\\Does not like burritos&81&54&135\\Total&110&95& 205\end{array}\right]

The conditional relative frequencies are presented as follows;

Conditional \ relative \ frequency \ (row)\\\begin{tabular}{|l|c|c|c|}& Cond. Rel. Frequency&&Total\\Likes burritos&29 \div 70 \approx 0.414&41 \div 70 \approx 0.586 &70 \div 70 = 1 \\Does not like burritos&81 \div 135 = 0.6&54 \div 135= 0.4&135 \div 135 = 1\end{array}\right]

Conditional\  Relative \ Frequencies \ (column)\\\begin{tabular}{|l|c|c|c|}&Like hamburgers&Does not like hamburgers\\Likes burritos&29 \div 110 \approx 0.263&41 \div 95 \approx   0.432\\Does not like burritos&81 \div 110 \approx 0.763&54 \div 95  \approx 0.568 \\&110 \div 110 = 1&95 \div 95 = 1\end{array}\right]

A strong association variables relates to how much a variable depends on another variable, which is the level of relationship.

Based on the above relative frequency tables, we have that the data point

for those that like hamburger (29, 81) is such that only approximately 26.3%

of those that like hamburgers like burritos, while 76.3% that like hamburger

do not like burritos, which can be interpreted as follows;

Majority of customers that like hamburgers (76.3%) do not like burritos

Therefore;

  • A data point that has the strongest association is the data point for the customers that like hamburgers and do not like burritos which is <u>81</u>.

Learn more conditional relative frequency table

brainly.com/question/7013423

brainly.com/question/2815014

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