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marishachu [46]
3 years ago
7

The graph shows the distance, y in miles, of a moving train froma station for a certain period of time, x, in hours:

Mathematics
1 answer:
nlexa [21]3 years ago
7 0
The constant speed or the mph is 150 miles per hour
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The length of a rectangle is five inches less than twice it’s width. If the rectangle has a perimeter of 80 inches, find the len
yawa3891 [41]

Answer:

Width of the rectangle  = 15 inches

Length of the rectangle  = 25 inches

Step-by-step explanation:

Let the width of the rectangle =  k inches

So, the length of the rectangle =   (2k -5) inches

Perimeter = 80 in

Perimeter of a rectangle = 2 (Length + Width)

⇒  80 = 2(k + (2k -5)

or 80 = 6k - 10

⇒ 6k = 80 + 10 = 90

or  k = 90 / 6

⇒ k = 15

So the width of the rectangle  = k  = 15 inches

And the length of the rectangle =  2k -5 = 2 x 25  - 5 = 25 inches

5 0
3 years ago
PLEASE I NEED HELP I HAVE NO IDEA WHAT THE ANSWERS ARE
Ivenika [448]

Answer:

Sector AOB: 3.87

Sector BOC: 7.74

Sector COD: 5.16

Sector DOE: 3.01

Sector AOE: 11.19

Explanation:

Equation used: S=\frac{r^2*a}{2}

4 0
2 years ago
Value of 5^-3 x 2^-1
Andreyy89

Answer: 1/250

Step-by-step explanation:

5^-3 × 2^-1

=> 1/5³ × 1/2

=> 1/125 × 1/2

=> 1/250

mark as brainly plss

3 0
3 years ago
An element with mass 510 grams decays by 26.3% per minute. How much of the element is remaining after 7 minutes, to the nearest
Eddi Din [679]

A decay rate of 26.3% per minute means that for every minute that passes, there remains 73.7% of the amount of the substance available at the end of the previous minute.

If a_0 is the starting amount, and a_i is the amount left after i minutes, then

a_1=0.737a_0

a_2=0.737a_1=0.737^2a_0

a_3=0.737a_2=0.737^3a_0

and so on, such that

a_7=0.737^7a_0

We have a_0=510 grams at the start, so after 7 minutes we're left with

a_7=0.737^7(510)\approx60.2\,\rm g

4 0
3 years ago
What is the range of y= sec-'(x)? PreCal, send help please!!
beks73 [17]

Given:

The function is:

y=\sec^{-1}(x)

To find:

The range of the given function.

Solution:

We have,

y=\sec^{-1}(x)

The range of secant inverse function is:

Range=\{y|0\leq y\leq \pi , y\neq \dfrac{\pi}{2}\}

The range of the given function in interval notation is:

Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ]

Therefore, the correct option is C.

6 0
3 years ago
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