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3 years ago

The graph shows the distance, y in miles, of a moving train froma station for a certain period of time, x, in hours:

Mathematics

1 answer:

nlexa [21]3 years ago

7 0

The constant speed or the mph is 150 miles per hour

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The length of a rectangle is five inches less than twice it’s width. If the rectangle has a perimeter of 80 inches, find the len

yawa3891 [41]

Answer:

Width of the rectangle = 15 inches

Length of the rectangle = 25 inches

Step-by-step explanation:

Let the width of the rectangle = k inches

So, the length of the rectangle = (2k -5) inches

Perimeter = 80 in

Perimeter of a rectangle = 2 (Length + Width)

⇒ 80 = 2(k + (2k -5)

or 80 = 6k - 10

⇒ 6k = 80 + 10 = 90

or k = 90 / 6

⇒ k = 15

So the width of the rectangle = k = 15 inches

And the length of the rectangle = 2k -5 = 2 x 25 - 5 = 25 inches

5 0

3 years ago

PLEASE I NEED HELP I HAVE NO IDEA WHAT THE ANSWERS ARE

Ivenika [448]

Answer:

Sector AOB: 3.87

Sector BOC: 7.74

Sector COD: 5.16

Sector DOE: 3.01

Sector AOE: 11.19

Explanation:

Equation used: $S=\frac{r^2*a}{2}$

4 0

2 years ago

Value of 5^-3 x 2^-1

Andreyy89

Answer: 1/250

Step-by-step explanation:

5^-3 × 2^-1

=> 1/5³ × 1/2

=> 1/125 × 1/2

=> 1/250

mark as brainly plss

3 0

3 years ago

An element with mass 510 grams decays by 26.3% per minute. How much of the element is remaining after 7 minutes, to the nearest

Eddi Din [679]

A decay rate of 26.3% per minute means that for every minute that passes, there remains 73.7% of the amount of the substance available at the end of the previous minute.

If $a_0$ is the starting amount, and $a_i$ is the amount left after $i$ minutes, then

$a_1=0.737a_0$

$a_2=0.737a_1=0.737^2a_0$

$a_3=0.737a_2=0.737^3a_0$

and so on, such that

$a_7=0.737^7a_0$

We have $a_0=510$ grams at the start, so after 7 minutes we're left with

$a_7=0.737^7(510)\approx60.2\,\rm g$

4 0

3 years ago

What is the range of y= sec-'(x)? PreCal, send help please!!

beks73 [17]

Given:

The function is:

$y=\sec^{-1}(x)$

To find:

The range of the given function.

Solution:

We have,

$y=\sec^{-1}(x)$

The range of secant inverse function is:

$Range=\{y|0\leq y\leq \pi , y\neq \dfrac{\pi}{2}\}$

The range of the given function in interval notation is:

$Range=\left[0,\dfrac{\pi}{2}\right)\text{ and }\left( \dfrac{\pi}{2}, \pi\right ]$

Therefore, the correct option is C.

6 0

3 years ago