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4 years ago

12.6 pounds equals how many ounces

Mathematics

1 answer:

Stells [14]4 years ago

4 0

201.6 ounces
Hope this helps and please mark me as brainlest and like

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A box contains fifteen billiard balls, numbered 1 through 15. Anna draws a ball, records the number, and then returns it to the

Drupady [299]

The correct end part of the question says;

Find the probability of rolling an even number "then" an odd number

Answer:

Probability of rolling even, then odd = 56/225

Step-by-step explanation:

Now, the numbers are from 1 to 15.

Since we want find probability of even, then odd number, let's list all the even numbers first;

Even numbers from 1 to 15 are;

2, 4, 6, 8, 10, 12, 14

Odd numbers from 1 to 15 are;

1, 3, 5, 7, 9, 11, 13, 15

So, we have 7 even numbers and 8 odd numbers.

Probability of even is = 7/15

Probability of odd is = 8/15

Thus,probability of rolling even, then odd is;

P(even, then odd) = 7/15 x 8/15 = 56/225

6 0

4 years ago

If cos() = − 2 3 and is in Quadrant III, find tan() cot() + csc(). Incorrect: Your answer is incorrect.

nydimaria [60]

Answer:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

Step-by-step explanation:

Given

$\cos(\theta) = -\frac{2}{3}$

$\theta \to$ Quadrant III

Required

Determine $\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

We have:

$\cos(\theta) = -\frac{2}{3}$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$\sin^2(\theta) + (-\frac{2}{3})^2 = 1$

$\sin^2(\theta) + (\frac{4}{9}) = 1$

Collect like terms

$\sin^2(\theta) = 1 - \frac{4}{9}$

Take LCM and solve

$\sin^2(\theta) = \frac{9 -4}{9}$

$\sin^2(\theta) = \frac{5}{9}$

Take the square roots of both sides

$\sin(\theta) = \±\frac{\sqrt 5}{3}$

Sin is negative in quadrant III. So:

$\sin(\theta) = -\frac{\sqrt 5}{3}$

Calculate $\csc(\theta)$

$\csc(\theta) = \frac{1}{\sin(\theta)}$

We have: $\sin(\theta) = -\frac{\sqrt 5}{3}$

So:

$\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}$

$\csc(\theta) = \frac{-3}{\sqrt 5}$

Rationalize

$\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}$

$\csc(\theta) = \frac{-3\sqrt 5}{5}$

So, we have:

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)$

Substitute: $\csc(\theta) = \frac{-3\sqrt 5}{5}$

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}$

Take LCM

$\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}$

6 0

3 years ago

SOMEONE PLEASE HELP, THIS PERSON NEEDS HELP HERE ILL GIVE YOU THE LINK AND IF YOU HELP THAT PERSON ILL MARK BRAINLIEST PLEASE HE

Y_Kistochka [10]

Answer: it dose not show anything

Step-by-step explanation:

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3 years ago

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A prism has a length of 5 meters, height of 6 meters, and width of 1 meter.

Svetradugi [14.3K]

Answer: 30 m3 (meters cubed)

Step-by-step explanation:

To get the volume of a rectangular prism, multiply the width times the length times the height.

1 x 5 x 6 = 30

Add the unit label

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3 years ago

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What is the name for the distance between the crest and trough of wave?

devlian [24]

Answer:

wave height

Step-by-step explanation:

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3 years ago

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