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Akimi4 [234]
2 years ago
15

Who will get the rolls done first ?

Mathematics
2 answers:
AysviL [449]2 years ago
8 0
Nora:
8 rolls per 10 min = 8/10 roll/min
= 4/5 roll per min

Eli:
10 rolls per 12 min = 10/12 roll/min
= 5/6 roll per min

Eli is faster; 5/6 > 4/5



Gekata [30.6K]2 years ago
7 0
Hello!

Divide the amount of rolls they can make (10) and (8) by the amount of time they have (40 mins):

40/10 = 4
40/8 = 5

So, Eli will finish making the rolls first.

I hope that was helpful! c:
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Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

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Where:

S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

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\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

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\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

With these we can find the sums:

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

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Nowe we can find the means for x and y like this:

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Answer:

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