Answer:
18.4km/h
Step-by-step explanation:
9.2km/.5hours=
18.4km/h
The equivalent expression is 1.05t and then 24 x 0.05 equals 1.2 so 25.2
Answer:
.Lower quartile = 3.5
Step-by-step explanation:
Rearranging the data from lowest to highest.
2, 3, 4, 5, 6, 7, 8, 9 , 10, 15
First finding the median to make it easier to find the lower quartile.
median : 6 and 7 but right now they're irrelevant so we don't honestly need to work that out.
The lower quartile would be 3 and 4
3+4= 7 divide by 2 = 3.5 is your lower quartile
Answer:
The population of the town at the end of 2017 was 65,550.
Step-by-step explanation:
The population of the town was 60,000 in the beginning of 2016.
In 2016, the total population is increased by 15%.

Therefore the population is increased by 9000 and the population of the town at the end of 2016 was

In 2017, the total population is decreased by 5%.

Therefore the population is decreased by 3450 and the population of the town at the end of 2017 was

Therefore the population of the town at the end of 2017 was 65,550.
keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)
