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pishuonlain [190]
3 years ago
12

Which values of x satisfy this equation?

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0
1.425 and 17.57 satisfy the equation.
Olegator [25]3 years ago
8 0

Answer:                

Step-by-step explanation:


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Hey there! I know this is prob really simple and I am beginning to understand it, but my problem is
gulaghasi [49]

Answer:

sec(60) = 2

Step-by-step explanation:

sec(theta) = 1/cos(theta)

theta = 60o

cos(60) = 1/2 = 0.5

sec(theta) = 1/0.5 = 2

8 0
3 years ago
Diego’s family car holds 14 gallons of fuel. Each day the car uses 0.5 gallons of fuel. A warning light comes on when the remain
sasho [114]

Answer:

4.5 gallons

Step-by-step explanation:

yes correct

5 0
3 years ago
(05.02 MC)
Elanso [62]

His work should have looked like this.

2x + y = 5
x − 2y = 10

y = 5 − 2x
x − 2(5 − 2x) = 10
x − 10 + 4x = 10
5x − 10 = 10                  When he added in both sides, he subtracted 10 from 10,
5x = 20                      instead of adding 10 from 10 to make 20.
x = 4
2(4) + y = 5
8 + y = 5

y = -3

4 0
3 years ago
Helppp please needed before tomorrow!!!!!!!!!!​
mel-nik [20]

Answer:

The function is 200+50t (t= # of months)

Step-by-step explanation:

The best way to do this is to look at the question, and see no matter what, we have to pay 200 dollars to start. After which, they charge 50 bucks a month. Knowing this, we can make a function using f(x). Let C(t)= cost. Included is that graph. So for these questions, we need to see that there is an independent and a dependent variable, and we need to see that cost is affected by time. Hope this helps.

3 0
2 years ago
A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r
eduard

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

            Radius= 1.5 m

            Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= 2\pi rh

Considering, π= 3.14

⇒ lateral surface area of cylinder= 2\times 3.14\times 1.5\times 2.5

⇒ lateral surface area of cylinder= 23.55 \ m^{2}

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= \frac{16500}{23.55} = 700.6369 \approx 701

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

8 0
3 years ago
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