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3 years ago

Which values of x satisfy this equation?

Mathematics

2 answers:

Alinara [238K]3 years ago

8 0

1.425 and 17.57 satisfy the equation.

Olegator [25]3 years ago

8 0

Answer:

Step-by-step explanation:

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4. Solve the equation.

shusha [124]

Answer:

=1187n

Step-by-step explanation:

5n+1182n=?

=1187n

6 0

2 years ago

Drag and drop the correct surface area to match the cube. cube with edge length = 3.2 m 12.8 m²19.2 m²51.2 m²61.44 m²

Ira Lisetskai [31]

- Surface Area of a Cube = 6(L)²
- Surface Area of this cube = 6(3.2)²
= 61.44 m²

3 0

3 years ago

A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func

djyliett [7]

Answer:

$y=120 * 1.1^x$ --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

$x \to months$

$y \to mice$

So, we have:

$(x_1,y_1) = (0,120)$ --- Monday

$(x_2,y_2) = (1,132)$ --- One month later

Required

The function

The function is represented as:

$y=ab^x$

In $(x_1,y_1) = (0,120)$ , we have:

$120 = a * b^0$

$120 = a * 1$

$120 = a$

$a=120$

In $(x_2,y_2) = (1,132)$ , we have:

$132 = a * b^1$

$132 = a * b$

Substitute: $a=120$

$132 = 120 * b$

Solve for b

$b = \frac{132}{120}$

$b = 1.1$

So, the function is:

$y=ab^x$

$y=120 * 1.1^x$

To calculate the monthly rate (r), we have:

$y =a(1 + r)^x$

Compare to: $y =ab^x$

$1 + r = b$

Make r the subject

$r = b-1$

Substitute $b = 1.1$

$r = 1.1-1$

$r = 0.1$

Express as percentage

$r = 0.1*100\%$

$r = 10\%$

5 0

3 years ago

Guy what 5x4 please help me

Archy [21]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Each month at Sea Stars, the

Tom [10]

Answer:

A good rule is to change 10 to 15 percent of the water each week. If your tank is heavily stocked, bump that up to 20 percent each week. A lightly stocked aquarium can maybe get by for two to four weeks, but this should be the maximum length of time between water changes.

Step-by-step explanation:

This is the correct answer you want

Please follow me

4 0

3 years ago