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Arlecino [84]
3 years ago
12

What is the hypotenuse

Mathematics
1 answer:
diamong [38]3 years ago
8 0

Answer:

13

Step-by-step explanation:

<em>c</em> is the hypotenuse. c = √a^2+b^2. To clarify, both a squared and b squared should be under the square root symbol.

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Maths question is here<br> 9+92*12312
atroni [7]

Answer:

it would be 101 i believe

3 0
3 years ago
Read 2 more answers
Does the line whose equation is 4/3 x + 8 pass through the point (9,20)
sergey [27]

Answer: yes

Step-by-step explanation: slope is 4/3 and y intercept is 8

m= Y-20/0-9

4/3= y-20/-9

4/3 x -9 = y-20

-12 = y-20

Y=20-12

Y=8

5 0
3 years ago
Find the degree of the polynomial b5 + 2b3 + 7.
scoray [572]

Answer:

5

Step-by-step explanation:

b^5 + 2b^3 + 7

Here,

degrees are 5 and 3.

The degree of the polynomial is the <u>highest / greatest number</u> in the degree.

Out of 3 and 5

5 is the highest / greatest number.

Hence,

the degree of the given polynomial is 5.

4 0
2 years ago
I don’t remember how I get the answer to this. I have the answer key though. Please help, I have a test in an hour
mrs_skeptik [129]

Answer:

  f(x) = (x -2)(x -1+3i)(x -1-3i)

Step-by-step explanation:

You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.

In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.

Of course, you know that for zeros a, b, and c, the linear factors are ...

  f(x) = (x -a)(x -b)(x -c)

Here, we have a=2, b=1-3i, c=1+3i.

  f(x) = (x -2)(x -1+3i)(x -1-3i)

5 0
3 years ago
Read 2 more answers
The area (A) of a circle with a radius of r is given by the formula and its diameter (d) is given by . Arrange the equations in
ella [17]

Answer:

see explanation

Step-by-step explanation:

A = πr² ← r is the radius and r = \frac{1}{2} d ← d is the diameter

Hence

π (\frac{1}{2} d)² = A, that is

\frac{d^2\pi }{4} = A ( multiply both sides by 4 )

d²π = 4A ( divide both sides by π )

d² = \frac{4A}{\pi } ( take the square root of both sides )

d = \sqrt{\frac{4A}{\pi } }

7 0
3 years ago
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