Question

20 POINTS!

Answer 1

Answer:

1. 3rd option

2. 2nd option

Step-by-step explanation:

Answer 2

Answer:

$y+1=\dfrac{1}{3}(x+2)$ - point-slope form

$f(x)=\dfrac{1}{3}x-\dfrac{1}{3}$ - function notation

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the graph we have the points (-2, -1) and (1, 0).

Substitute:

$m=\dfrac{0-(-1)}{1-(-2)}=\dfrac{1}{3}$

$y-(-1)=\dfrac{1}{3}(x-(-2))$

$y+1=\dfrac{1}{3}(x+2)$ - point-slope form

$y+1=\dfrac{1}{3}(x+2)$          use the distributive property

$y+1=\dfrac{1}{3}x+\dfrac{2}{3}$           subtract 1 = 3/3 from both sides

$y=\dfrac{1}{3}x-\dfrac{1}{3}$