Answer:
cbsdhcbsufbufbubsdubsusfsdfsdfsd
Step-by-step explanation:
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
I think it is 4.4329. I hope it's right.
Answer: option A:12.
Explanation:
Since, rolling a die and tossing a coin are independent events, the sample space of both events is the product of the outcomes for each event, i.e 6 × 2 = 12.
You can check that here:
roll a die toss a coin
1 head
1 tail
2 head
2 tail
3 head
3 tail
4 head
4 tail
5 head
5 tail
6 head
6 tail
So, as you see for each outcome of the event roll a die there are two different possible different outcomes for the event toss a coin; since there are 6 different outcomes for the die, the total number of possibilities is 6 × 2 = 12
-2 , -14/5 , -13/5, -12/5 , -11/5
-2, -2.8 , -2.6, -2.4, -2.2
