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3 years ago

9

A teacher brings 8 birdies and 32 rackets to a physical education class of 30 students playing badminton. what is the ratio of b

irdies to students for this class?

1 answer:

ipn [44]3 years ago

5 0

To get your ratio of birdies do 8/32/30 and that will give you your ratio

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Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 (

Sonja [21]

Answer:

a) Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

$\bar X = 41.538$

$s = 5.317$

b) 44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

$\bar X = 43.615$

$s= 5.583$

c) 3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

$\bar X= 3.462$

$s = 0.443$

d) As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3.462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

Step-by-step explanation:

For this case we can use the following formulas for the mean and standard deviation:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Part a

Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

And if we calculate the mean we got:

$\bar X = 41.538$

$s = 5.317$

Part b

For this case we know that each value present a 5% of rise so we just need to multiply each value bu 1.05 and we have this new dataset:

44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

And if we calculate the new mean and deviation we got:

$\bar X = 43.615$

$s= 5.583$

Part c

The new dataset would be each value divided by 12 so we have:

3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

And the new mean and deviation would be:

$\bar X= 3.462$

$s = 0.443$

Part d

As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3,462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

5 0

4 years ago

Jenny can swim 10 laps In 5 minutes. How many laps should she swim in 1/3 of an hour?

DIA [1.3K]

1/3 of an hour is 20 minutes. If show 10 laps in 5 minutes, just divide 20 by 5, which gives you 4, then multiply 4 times 10. She can swim 40 laps in 1/3 of an hour. Hope that helps. Mark Brainliest if it does. Thank you!

4 0

3 years ago

your automobile insurance semiannual premium is 750 and you have 1050 deductible per incident. In a particularly bad year, you h

nataly862011 [7]

Answer:

$3600

Step-by-step explanation:

In each case, the repair cost exceeded the deductible, so your out-of-pocket cost for 2 repairs is ...

2 × $1050 = $2100

In addition, you had to pay the premium of $750 per 6-month period, or $1500 per year, so your total was ...

$2100 +1500 = $3600 . . . out-of-pocket total

6 0

4 years ago

In a field, dry fodder for the cattle is heaped in a

ipn [44]

Answer:

volume of fodder=1/3pie R^2h= $\frac{1}{3} *\frac{22}{7} * (3.6)^2 *2.1=28.51m^3$

l^2=r^2+h^2

l^2=(2.1)^2+(3.6)^2

l^2=4.441+12.96=17.37

l= $\sqrt{17.37}$ =4.17m

minimum area of polythene to cover fodder=pieRl= $\frac{22}{7} *3.6*4.17=47.18m^2$

the volume of fodder is $28.51m^3$ and minimum area of polythene to cover fodder in the rainy seasonv47.18m^3

3 0

3 years ago

When lines are at the same distance apart over their lengths they are ?

svlad2 [7]

Answer:

parallel lines

Step-by-step explanation:

parallel lines are lines that do not meet each other

7 0

3 years ago