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Luda [366]
3 years ago
7

What is the value of d in the equation d−1.9=9.1 ?

Mathematics
2 answers:
andriy [413]3 years ago
8 0
The answer would be d += 11.  Because 1.9 + 9.1 = 11 hop it helps :)
inn [45]3 years ago
6 0
To get your answer, just add 9.1+1.9. You get 11.

You can double check by replacing 11 with D in the equation.

11-1.9 does equal 9.1 so the answer is correct.
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John is five years older than his sister. The product of their present ages is 150.
photoshop1234 [79]
Took 3 of us in grade 10 but johns present age is 77.5 and his sister is 72.5
5 0
3 years ago
If 97 of 200 is 100% then how much of 200 is 112%
pickupchik [31]
To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 112 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 112 is 100%, so we can write it down as 112=100%.
4. We know, that x is 200% of the output value, so we can write it down as x=200%.
5. Now we have two simple equations:
1) 112=100%
2) x=200%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
112/x=100%/200%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 200% of 112

112/x=100/200
(112/x)*x=(100/200)*x - we multiply both sides of the equation by x
112=0.5*x - we divide both sides of the equation by (0.5) to get x
112/0.5=x
224=x
x=224

now we have:
200% of 112=224



●I tried my best I was never good with percentages my least favorite.... Please let me know if you got it wrong. If you do I'm sorry.
3 0
3 years ago
Here is the next one jaded :))
Ksju [112]

Answer:

x = 5.56

Step-by-step explanation:

Sin(17) = \frac{x}{19}

=> Isolate the "x"

Sin(17) * 19 = x

5.56 = x

Hope this helps!

6 0
3 years ago
An arched drainage culvert can be modelled by the function:
Zanzabum

Substitute 136.5 for y.

136.5=\frac{x(191-x)}{60}

8190=x(191-x)

8190=191x-x^{2}

x^{2} -191x+8190=0

Compare this equation with ax^{2} +bx+c=0

a = 1, b = - 191, c = 8190

x=\frac{-b+\sqrt{b^{2}-4ac } }{2} or

x=\frac{-b-\sqrt{b^{2}-4ac } }{2}

x=\frac{191+\sqrt{191^{2}-4(1)(8190) } }{2} or

x=\frac{191-\sqrt{191^{2}-4(1)(8190) } }{2}

x=\frac{191+\sqrt{36481-32760 } }{2} or

x=\frac{191-\sqrt{36481-32760 } }{2}

x=\frac{191+\sqrt{3721 } }{2} or

x=\frac{191-\sqrt{3721 } }{2}

x=\frac{191+61}{2} or

x=\frac{191-61}{2}

x=\frac{252}{2} or

x=\frac{130}{2}

x = 126 or x = 65

Hence, the points on the curve are (65, 136.5) and (126, 136.5).

The width of the air space is the distance between these points.

Width = \sqrt{(x_{2}- x_{1})^{2} +( y_{2}- y_{1}) ^{2}

= \sqrt{(126- 65)^{2} +(136.5-136.5) ^{2}

= 126 - 65

= 61

Hence, width of the air space is 61m.



5 0
3 years ago
Help pls and thank you!!!
max2010maxim [7]

Answer:

Consistent and independent

Step-by-step explanation:

The only touch at one point and they are not the same line and are not parallel

5 0
3 years ago
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