4 years ago

What is the value of d in the equation d−1.9=9.1 ?

Mathematics

2 answers:

andriy [413]4 years ago

8 0

The answer would be d += 11. Because 1.9 + 9.1 = 11 hop it helps :)

inn [45]4 years ago

6 0

To get your answer, just add 9.1+1.9. You get 11.

You can double check by replacing 11 with D in the equation.

11-1.9 does equal 9.1 so the answer is correct.

You might be interested in

denis23 [38]

The answer is none. There are no solutions

6 0

3 years ago

Work out the number that is halfway between 27 times 38 and 33 times 38.

lutik1710 [3]

$27*38=1026\\
33*38=1254\\
x-between\ number\\
x=\frac{1026+1254}{2}\\
x=\frac{2280}{2}\\
x=1140$

4 0

3 years ago

(4x+2) 2<br><br> the 2 is an exponent

VikaD [51]

Answer:

16x^2+16x+4

Step-by-step explanation:

3 0

3 years ago

X3= one over eight what's the answer for that?

Black_prince [1.1K]

X^3 = 1/8
x^3 = (1/2)^3
x = 1/2

hope it helps

6 0

3 years ago

Simplify 2√2-√3<br> ---------------<br> √2+√3

serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

$= 2 + 4 \sqrt{6}$

6 0

2 years ago