Answer:
See below for answers
Step-by-step explanation:
1) Parent functions are essentially non-transformed functions, so y=x^2 would be the parent function of y=x^2+1 for example since y=x^2 has no transformations while y=x^2+1 does.
2) Since certain x-values won't be defined for the function, you need to restrict the domain. For example, in the function f(x)=1/x, obviously x=0 is undefined for the function, so we would need to restrict the domain.
3) Not sure what you mean by name graph; no context given
4) Also no context given
5) The equation would be y=(x+5)^4-3
Rewriting the left-hand side as follows,
![(2\cos\theta-6\sin \theta)^2 +(6\cos \theta+2\sin \theta)^2\\\\=4\cos^2 \theta-24\cos \theta \sin \theta+36 \sin^2 \theta+36 \cos^2 \theta+24 \cos \theta \sin \theta+4 \sin^2 \theta\\\\=40\cos^2 \theta+40 \sin^2 \theta\\\\=40(\cos^2 \theta+\sin^2 \theta)\\\\=40](https://tex.z-dn.net/?f=%282%5Ccos%5Ctheta-6%5Csin%20%5Ctheta%29%5E2%20%2B%286%5Ccos%20%5Ctheta%2B2%5Csin%20%5Ctheta%29%5E2%5C%5C%5C%5C%3D4%5Ccos%5E2%20%5Ctheta-24%5Ccos%20%5Ctheta%20%5Csin%20%5Ctheta%2B36%20%5Csin%5E2%20%5Ctheta%2B36%20%5Ccos%5E2%20%5Ctheta%2B24%20%5Ccos%20%5Ctheta%20%5Csin%20%5Ctheta%2B4%20%5Csin%5E2%20%5Ctheta%5C%5C%5C%5C%3D40%5Ccos%5E2%20%5Ctheta%2B40%20%5Csin%5E2%20%5Ctheta%5C%5C%5C%5C%3D40%28%5Ccos%5E2%20%5Ctheta%2B%5Csin%5E2%20%5Ctheta%29%5C%5C%5C%5C%3D40)
Answer:
A
Step-by-step explanation:
If you plot the point on a cartesian plane you see it is on the y axis
Answer: 18
Step-by-step explanation: The formula for circumference is 2piR. Since 2piR = 36pi, you can cancel out the pi's which makes it 2r = 36. Divide by 2 on both sides and you get r = 18.
Answer:
B. (1,-8)
Step-by-step explanation:
Slope of the first one:
(-6-0)/(0--3) = -6/3 = -2
y = -2x - 6
3y + 30 = 6x
y + 10 = 2x
-2x - 6 + 10 = 2x
4 = 4x
x = 1
y = -2(1) - 6
y = -8