Answer:
a)
The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.
The incenter is located at the intersection of bisectors of the interior angles of a triangle.
b)
The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.
The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.
c)
<em>See the attachment</em>
The blue lines and their intersection shows the incenter.
The red lines and their intersection shows the circumcenter.
As we see the red point- the <u>circumcenter </u>is closer to vertex B.
Answer:
The current area of the circle is 81π in².
They want to " 'decrease' " the radius to 9 in.
First, find the current radius for the current circle.
Areas of circle = πr²,
81π = πr²
First, divide π from both sides of the equation:
(81π)/π = (πr²)/π
r² = 81
Isolate the variable, r. Root both sides of the equation:
√(r²) = √(81)
r = √( 9 * 9) = 9
The radius currently is 9 in.
The NBA is not making any changes at all, therefore the question will be void. (Note that the other answer choice is -9, however, you cannot have a negative measurement, therefore, the answer is voided).
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