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blsea [12.9K]
2 years ago
8

Consider the system of equations, y = f(x) and y= g(x), where

Mathematics
1 answer:
NARA [144]2 years ago
8 0

Answer:

  (x, y) = (3, 26)

Step-by-step explanation:

I like to solve systems of equations like this by graphing. A graphing calculator easily shows the solution for both x and y.

  (x, y) = (3, 26)

__

As an alternative, here, the equations can be subtracted.

  y = f(x)

  y = g(x)

  0 = f(x) - g(x)  . . . .  subtract the second equation from the first

  0 = 11x -7 -(3x +17)

  0 = 8x -24 . . . . simplify

  0 = x -3 . . . . . . .divide by 8

  3 = x

Now, we can substitute into either equation:

  y = g(x) = 3(3) +17 = 26

The solution is (x, y) = (3, 26).

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Read 2 more answers
Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)
morpeh [17]

Answer:

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is odd then x> 0 is true statement.

\forall x\in D if x is even then x≤0 is false statement.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) \forall x\in D if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (B) \forall x\in D if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

\forall x\in D if x is odd then x> 0 is true statement.

Part (C) \forall x\in D if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

\forall x\in D if x is even then x≤0 is false statement.

Part (D) \forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

\forall x\in D If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) \forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

\forall x\in D if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0
3 years ago
State whether or not the following triangles are similar. If not, explain why not. If so, write a similarity statement
valentinak56 [21]

9514 1404 393

Answer:

  a) ∆RLG ~ ∆NCP; SF: 3/2 (smaller to larger)

  b) no; different angles

Step-by-step explanation:

a) The triangles will be similar if their angles are congruent. The scale factor will be the ratio of any side to its corresponding side.

The third angle in ∆RLG is 180° -79° -67° = 34°. So, the two angles 34° and 67° in ∆RLG match the corresponding angles in ∆NCP. The triangles are similar by the AA postulate.

Working clockwise around each figure, the sequence of angles from lower left is 34°, 79°, 67°. So, we can write the similarity statement by naming the vertices in the same order: ∆RLG ~ ∆NCP.

The scale factor relating the second triangle to the first is ...

  NC/RL = 45/30 = 3/2

__

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