All categories

3 years ago

So yeah and can you explain how to do it thanks this be a lot of help

Mathematics

2 answers:

Zinaida [17]3 years ago

6 0

Answer: -29a-6b+59c
You need to combine like terms

Aleksandr [31]3 years ago

3 0

Answer:

-29a - 6b + 59c

Step-by-step explanation:

First, keep in mind that only like terms can be combined.

5a + 7b - 12a + 6c - 13b - 22a + 53c

You can rearrange them to make it easier:

5a - 12a - 22a + 7b - 13b + 6c + 53c

-29a - 6b + 59c

You might be interested in

What is the approximate volume of the cone?

KonstantinChe [14]

Answer:

157 cm³

Step-by-step explanation:

Given

Radius (r) = 5 cm

height (h) = 6 cm

Volume of the cone (V) = ?

We have the formula

V = 1/3 *π*r²*h

V = 1/ 3 * 3.14 * 5² * 6

V = 157 cm³

Hope it will help :)

7 0

3 years ago

What is 946 divided by 11?

timama [110]

Answer: 946 ∻ 11 = 86

3 0

3 years ago

Find the volume of a rectange 9 in., 3 in., 6 in.

aleksley [76]

V= length x width x height.
9 x 3 x 6 =162
162 inches cubed!

4 0

3 years ago

Read 2 more answers

An art class is making a mural for their school which has a triangle drawn in the middle. The length of the bottom of the triang

jolli1 [7]

Answer:

The perimeter of the triangle can be expressed as 5x + 18.

Step-by-step explanation:

Perimeter of an object is the sum of the length of its sides.

For the required triangle, we have;

length of the base = x

length of the second side = 3x + 9

length of the third side = x + 9

Perimeter of the triangle = length of the base + length of the second side + length of the third side

= x + (3x + 9) + (x + 9)

= x + 3x + 9 + x + 9

= 5x + 18

The perimeter of the triangle can be expressed as 5x + 18.

8 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago