Answer:
There is exactly one more real solution or there is exactly one more complex solution
Step-by-step explanation:
A quadratic equation is a polynomial of degree two
What this means is that a polynomial has two answers.
Now, from the question, we have an answer already which is a real root
Then the other answer which we do not have can take the form of two answers
It can either be a complex root or other wise be a real root
So the answer to this question is that ;
There is exactly one more real solution or there is exactly one more complex solution
Answer:
-5v+4
Step-by-step explanation:
Remove the parentheses and combine the like terms:
-2v + (-4) + 8 + (-3v)
-2v -4 + 8 -3v [Remove parentheses]
-5v +4 [Combine like terms]
<u>-5v +4 </u>
Answer:
Step-by-step explanation:
x
=
0
I think that it would be C, but I am debating on C and D. I'm pretty confident that it's C, though. Pretty sure.
To solve this problem, we have to figure out a rule for the function. We are told that it is a two-step rule, so it is most likely the input multiplied by a coefficient plus a constant. Let’s let the input be represented by the variable x and the output be represented by the variable y. Using our knowledge, we can see that the outputs are close to triple the input, so we set up the preliminary equation:
y = 3x + b,
where b is a constant. If we want to solve for b, we must plug in one of our input/output pairs. If we plug in (5,16), we get the following:
16 = 3(5) + b
16 = 15 + b
1 = b
Then, we should substitute in this value into our equation and check our work.
y = 3x + 1
If we plug in the other points, this equation yields a true statement, so we know it is correct.
Hope this helps!
