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Sergio039 [100]

3 years ago

7

(vii) log32 8=m Again please

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

log_(32)8= 3/5

Step-by-step explanation:

Log_(32)8 = m

write is as

32^m=8

(2^5)^m = 2^3

2^5m = 2^3

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

5m = 3

divide 5 on both sides to remove it from m

m= 3/5

Hope this helps!

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Write an inequality that represents the verbal expression. All real numbers less than 74

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What is the length of missing side JK? Round Answer to nearest tenth please.

zvonat [6]

Given:

Triangle LJK.

LJ = 89 in, LK = 28 in and m∠L = 42°

To find:

The length of missing side JK.

Solution:

LJ = k = 89

LK = j = 28

JK = l = ?

Using law of cosine:

$l^{2}=j^{2}+k^{2}-2 jk \cdot \cos L$

Substitute the given values.

$l^{2}=28^{2}+89^{2}-2 \cdot 28 \cdot 89 \cdot \cos 42^\circ$

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$l^{2}=784+7921-4984 \cdot (0.7431)$

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3 years ago

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Dafna1 [17]

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Step-by-step explanation:

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2 years ago

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I am Lyosha [343]

Answer:

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Step-by-step explanation:

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Type the correct answer in each box. If necessary, use / for the fraction bar(s).

Tom [10]

Given:

The values are $a=0.\overline{6},b=0.75$ .

To find:

The values of $ab$ and $\dfrac{a}{b}$ .

Solution:

We have,

$a=0.\overline{6}$

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Multiply both sides by 10.

$10a=6.666...$ ...(ii)

Subtracting (i) from (ii), we get

$10a-a=6.666...-0.666...$

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And,

$b=0.75$

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$b=\dfrac{3}{4}$

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$ab=\dfrac{2}{3}\times \dfrac{3}{4}$

$ab=\dfrac{1}{2}$

The quotient of a and b is:

$\dfrac{a}{b}=\dfrac{\dfrac{2}{3}}{\dfrac{3}{4}}$

$\dfrac{a}{b}=\dfrac{2}{3}\times \dfrac{4}{3}$

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3 years ago