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3 years ago

(vii) log32 8=m Again please

Mathematics

1 answer:

KonstantinChe [14]3 years ago

3 0

Answer:

log_(32)8= 3/5

Step-by-step explanation:

Log_(32)8 = m

write is as

32^m=8

(2^5)^m = 2^3

2^5m = 2^3

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

5m = 3

divide 5 on both sides to remove it from m

m= 3/5

Hope this helps!

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15. Which table correctly lists the x- and y-values for the equation 5x + y = 14?

Natalija [7]

Answer:

Step-by-step explanation:

Given

5x + y = 14 ( subtract 5x from both sides )

y = 14 - 5x

Substituting values of x into the right side allows the corresponding value of y to be found.

x = - 1 : y = 14 - 5( - 1) = 14 + 5 = 19

x = 0 : y = 14 - 5(0) = 14 - 0 = 14

x = 1 : y = 14 - 5(1) = 14 - 5 = 9

Hence the corresponding values of x and y are

x y

- 1 19

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4 years ago

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Answer:

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4 years ago

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4 years ago

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Nostrana [21]

Answer:

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2 years ago

6x^2-9x +2=0 solve the quadratic equation using the quadratic formula

balu736 [363]

<u>ANSWER: </u>

The roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

<u>SOLUTION:</u>

Given, quadratic equation is $6 x^{2}-9 x+2=0$ --- eqn (1)

We need to find the roots of given quadratic equation using quadratic formula.

Quadratic formula for general quadratic equation $a x^{2}+b x+c=0$ is $X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for eqn (1) a = 6, b= -9 and c = 2

$X=\frac{-(-9) \pm \sqrt{(-9)^{2}-4 \times6 \times 2}}{2 x 2}$

$X=\frac{9 \pm \sqrt{81-48}}{4}$

$\begin{array}{l}{X=\frac{9 \pm \sqrt{33}}{4}} \\ {X=\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}}\end{array}$

Hence the roots of $6 x^{2}-9 x+2=0$ are $\frac{9+\sqrt{33}}{4}, \frac{9-\sqrt{33}}{4}$

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3 years ago