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2 years ago

13

Sarah rides her bicycle 2.7 miles to school.She takes a different route home,which is 2.5 miles.How many miles does Sarah ride t

o and from school each day?

2 answers:

adell [148]2 years ago

8 0

5.2 miles to ride to and from school

aleksandrvk [35]2 years ago

3 0

5.2 miles per day to get to school and back...elementary was the days

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The steps below describe the construction of a line AG which is parallel to segment PQ and passes through a point A outside of P

Wittaler [7]

Answer:

“The width of the compass is adjusted to DE, and an arc is drawn from point F.”

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2 years ago

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The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When

atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

$A=w\ell$

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

$\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]$

By the Product Rule:

$\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w$

Since we know that dl/dt = 6 and that dw/dt = 5:

$\displaystyle \frac{dA}{dt}=5\ell + 6w$

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

$\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}$

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

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2 years ago

PLS ANSWER THE BELOW QUESTION AND I'LL MARK U AS BRAINLIST

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$a) \dfrac{3x}{2}-5=4$

Add 5 to both sides

$\dfrac{3x}{2}-5 +5 = 4 + 5\\\\\dfrac{3x}{2} = 9 \\\\Now \ multiply \ both \ sides \ by \ 2 \\\\\dfrac{3x}{2}*2 = 9*2\\\\3x = 18\\Now \ divide \ both \ sides \ by \ 3\\\\x =\dfrac{18}{3}\\\\$

x = 6

$b) \dfrac{x-3}{5} + 1 = -2\\\\\\Subtract \ 1 \ from \ both \ sides\\\\\dfrac{x-3}{5} = -2 -1\\\\\dfrac{x-3}{5} = -3\\\\Multiply \ both \ side \ by \ 5\\\\x - 3 = -3*5\\\\x -3 = -15\\\\$

Add 3 to both sides

x = -15 +3

x = -12

7 0

2 years ago

Read 2 more answers

1.20 x 10⁶<br><br>6.0 x 10⁵

omeli [17]

Answer:

$1.20 x 10^{6}=1,200,000\\\\6.0 x 10^{5}=600,000$

Step-by-step explanation:

You move the decimal place over 6 times for the first equation and 5 for the second equation.

Hope this helps! Have a great day! :)

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3 years ago

Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i

aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

$P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175$

Positive when there is raritanium:

98% of 13%

$P(A) = 0.98*0.13 = 0.1274$

What is the probability the rock sample actually contains raritanium?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967$

0.967 = 96.7% probability the rock sample actually contains raritanium

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2 years ago