3 years ago

P+t+t-p-t+ P + P + t - t-t=

1 answer:

Elza [17]3 years ago

6 0

3p-p it might not be but maybe

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devlian [24]

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Mrrafil [7]

Step-by-step explanation:

We have been given that AE=BE and $\angle1\cong \angle2$ .

We can see that angle CEA is vertical angle of angle DEB, therefore, $m\angle CEA=m\angle DEB$ as vertical angles are congruent.

We can see in triangles CEA and DEF that two angles and included sides are congruent.

$\angle 1\cong \angle 2$

$AE=BE$

$\angle CEA\cong\angle DEB$ or $\angle 3\cong \angle 4$

Therefore, $\Delta CEA\cong \Delta DEB$ by ASA postulate.

Since corresponding parts of congruent triangles are congruent, therefore CE must be congruent to DE.

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3 years ago

P+t+t-p-t+ P + P + t - t-t=​