Answer:
(2,-5) and (2,1).
Step-by-step explanation:
We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.
A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.
Standard form of a circle is
where, (h,k) is center and r is the radius.
Now, put x=2.
Taking square root on both sides.
So, the y-coordinates of the points are -5 and 1.
Therefore, the required points are (2,-5) and (2,1).
Do you mean a_(n+1), worded a sub (n+1)?
If so yes. If the function of the sequence is getting smaller or more negative with each term.
Answer:
The vertical one is the y axis and the horizontal one is the x axis.
Step-by-step explanation:
F(x) = x^2/2 + 2x + 1f(x) = 1/2 * (x^2 + 4x) + 1f(x) = 1/2 * (x^2 + 4x + 4) - 1/2 * (4) + 1f(x) = 1/2 * (x + 2)^2 - 1
The vertex is (-2, -1). The axis of symmetry is x = -2. The minimum value is -1. The maximum value is infinity.
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Answer:
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Step-by-step explanation:
