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scoray [572]
3 years ago
15

Please add this problem. 2 7/10 + 2 4/5=

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0
11/2 or 5.5 or 5 1/2
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Daniel is packing his bags for his vacation. He has
bulgar [2K]

Answer: 5

Step-by-step explanation:

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6 0
3 years ago
4x when x = 3/4 (I really need help)
hoa [83]
3/4 is 0.75 as a decimal so 4 x 0.75 = 3
8 0
3 years ago
Explain how a(b + c) can be rewritten as (b + c)a and as ba + ca.
jenyasd209 [6]

Answer:

#UseDistributiveProperty

Step-by-step explanation:

6 0
3 years ago
identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the
mrs_skeptik [129]

Given the function:

g(x)=cos4x

Let's find the amplitude and period of the function.

Apply the general cosine function:

f(x)=Acos(bx+c)+d

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

f(x)=cosx

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

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8 0
1 year ago
A triangular course for a canoe race is marked with buoys. The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg
balu736 [363]
<h2>The race is 1.2 miles long</h2>

Step-by-step explanation:

The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

\texttt{Length of first leg = }\frac{3}{10}miles\\\\\texttt{Length of second leg = }\frac{1}{2}miles\\\\\texttt{Length of third leg = }\frac{2}{5}miles

Now we need to find length of race

       \texttt{Total length = }\frac{3}{10}+\frac{1}{2}+\frac{2}{5}\\\\\texttt{Total length = }\frac{3}{10}+\frac{5}{10}+\frac{4}{10}\\\\\texttt{Total length = }\frac{3+5+4}{10}\\\\\texttt{Total length = }\frac{12}{10}\\\\\texttt{Total length = }1.2miles

The race is 1.2 miles long

7 0
3 years ago
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