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3 years ago

If each of the numbers in the following data set were multiplied by 26, what

Mathematics

1 answer:

torisob [31]3 years ago

4 0

The correct answer is C, 936.

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Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0

Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

$\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\$

Let the value a so, the value of $a_n$ and the value of $a_(n+1)$ is:

$\to a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}$

$\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}$

To calculates its series we divide the above value:

$\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\$

$= \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |$

$= \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\$

$= \frac{x^2}{2^2(n+1)^2}\longrightarrow 0$ for all x

The final value of the converges series for all x.

8 0

4 years ago

Use substitution to determine which of the following is a solution for x in the equation:

S_A_V [24]

Answer:

x = 6

Step-by-step explanation:

x+4−4=10−4

x=6

8 0

3 years ago

Read 2 more answers

If the sin 90º = 1, then which statement is true?

Natali [406]

in a right-triangle, like in the 1st Quadrant, cosine and sine are complements, so then

sin(x) = cos(90° - x)

cos(x) = sin(90° - x)

for this case, sin(<u>90°</u>) = cos(90° - <u>90°</u>), or just cos(0°) = 1.

6 0

3 years ago

Pls help me figure out this problem

andriy [413]

Answer:

[a] not sure but try

Step-by-step explanation:

5 0

3 years ago

if you have one and a half loaf of bread and you have twelve people. which size of bread will each get

Natalija [7]

Answer:

1/8 of a loaf

Step-by-step explanation:

Divide the 1.5 loafs by 12 people

7 0

3 years ago