Question

What is the slope of the line 6x+10y=8

Answer 1

Hi there!

The general equation of a slope-intercept line looks like this :

y = mx + b

Where "m" is the slope and "b" is the y-intercept.

First you need to isolate the y in your equation in order to have the right slope-intercept form :

6x + 10y = 8

Subtract 6x from each side of the equation

10y = 8 - 6x

Divide each side of the equation by 10

y = 0.8 - $\frac{6x}{10}$

y = 0.8 - $\frac{3x}{5}$

y = -$\frac{3}{5}x$ + 0.8

Now that you have your right form of equation, you can easily see that the slope is -$\frac{3}{5}$.

There you go! I really hope this helped, if there's anything just let me know! :)

Answer 2

First, get it into slope-intercept:

y = -3/5x + 4/5

The slope is -3/5