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Phantasy [73]
3 years ago
7

How does 4 digit addends have a 5 digit sum

Mathematics
1 answer:
denpristay [2]3 years ago
3 0
A 4 digit addends could have a 5 digit sum because of the rule of regrouping.
Regrouping is a situation where carrying and borrowing is involves. So let’s have an example

  8999
<span>+5678
</span>14677

so in this example, we added 8999 to 5678.
9+8 = 17, so we bring down 7 and carry 1
9 + 7 = 16 + 1 = 17 , so again we bring down 7 carry 1
9 + 6 = 15 + 1 = 16, bring down 6 carry 1
8+5 = 13 + 1 =14, since this is our last number, bring down 14..
=> 14, 677
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Alex Ar [27]

Answer:

3 dogs and 2 cats.

Step-by-step explanation:

In this case we can solve it using a 2x2 system of equations, like this:

let x: number of cats

let y: number of dogs

So:

42.5 * x + 64 * y = 277

35.5 * x + 50.5 * y = 222.5 => x = (222.5 - 50.5 * y) /35.5

Replacing, we are left with that:

42.5 * (222.5 - 50.5 * y) /35.5 + 64 * y = 277

266.37- 60.45 * y + 64 * y = 277

64 * y - 60.45 * y = 277 - 266.37

3.55 * y = 10.63

y = 10.63 / 3.55

y = 2.99, about 3

Now to calculate x:

x = (222.5 - 50.5 * 3) /35.5

x = 2

Which means that it has a total of 3 dogs and 2 cats.

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3 years ago
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72 square feet

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A bag contains 2 black balls, 4 yellow balls and 4 white balls. Event A is defined as drawing a white ball on the first draw and
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Answer: P(B|A)=\dfrac{4}{9}

Step-by-step explanation:

Given: A bag contains 2 black balls, 4 yellow balls and 4 white balls.

Event A is defined as drawing a white ball on the first draw.

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P(B|A) is expressed as the conditional probability of occurring B given that A.

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