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lina2011 [118]
3 years ago
13

Simplify the expression: 9k+3k+8k

Mathematics
2 answers:
IrinaK [193]3 years ago
7 0

Answer:

20k

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients/Degrees

Step-by-step explanation:

<u>Step 1: Define</u>

9k + 3k + 8k

<u>Step 2: Simplify</u>

  1. Combine like terms (Add k):           12k + 8k
  2. Combine like terms (Add k):           20k
Savatey [412]3 years ago
3 0

Final Answer: 20k

Steps/Reasons/Explanation:

Because they are all one variable, you can just add them up.

Question: Simplify the expression: 9k+3k+8k.

<u></u>

<u>Step 1</u>: Addition.

20k

~I hope I helped you :)~

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Jason wants to eam money by raking leaves. He buys a rake that costs $30.00. He plans to charge $8.00 for each lawn that he rake
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Step-by-step explanation:

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3 years ago
4-It has been a bad day for the market, with 70% of securities losing value. You are evaluating a portfolio of 20 securities and
riadik2000 [5.3K]

Answer:

b) 0.0007

c) 0.4163

d) 0.2375

Step-by-step explanation:

We are given the following:

We treat securities lose value as a success.

P(Security lose value) = 70% = 0.7

Then the securities lose value follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 20.

a) Assumptions

  • There are 20 independent trials.
  • Each trial have two possible outcome: security loose value or security does not lose value.
  • The probability for success of each trial is same, p = 0.7

b) P(all 20 securities lose value)

We have to evaluate:

P(x = 20)\\= \binom{20}{0}(0.7)^0(1-0.7)^{20}\\= 0.0007

0.0007 is the probability that all 20 securities lose value.

c) P(at least 15 of them lose value.)

P(x \geq 15)\\= P(x=15) + P(x = 16) + P(x=17) + P(x=18) +P(x = 19) +P(x = 20)\\ \binom{20}{15}(0.7)^{15}(1-0.7)^{5} +...+ \binom{20}{20}(0.7)^{20}(1-0.7)^{0} \\=0.4163

d) P(less than 5 of them gain value.)

P(gain value) = 1 - 0.7 = 0.3

P(x < 5)\\= P(x=0) + P(x = 1) + P(x=2) + P(x=3) +P(x = 4)\\ \binom{20}{0}(0.3)^{0}(1-0.3)^{20} +...+ \binom{20}{4}(0.3)^{4}(1-0.3)^{16} \\=0.2375

7 0
4 years ago
Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum product
kkurt [141]
Ummm if its multiply then its 1 and 6. is its addition then its 1 and 5 or 6 and 0. if its divide it would be 6 and 1. is its subtraction then it would be 7 and 1 or 6 and 0

3 0
4 years ago
Please help! 9/4(7+3-4*9)
Serga [27]

Answer:

58.5

Step-by-step explanation:

This expression should be simplified using order of operations. According to order of operations or PEMDAS, complete any numbers in parenthesis then any exponents, multiplication, division, additions and subtraction moving left to right through each operation.

Begin with Parenthesis.

(7+3-4*9) - Multiply first

(7+3-36) - Then add/subtract left to right

10 - 36 = -26

Replace -26 where the parenthesis were in the original expression.

9/4 (-26)

234/4

58.5

6 0
3 years ago
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