Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
True Because the visual aids will provide better hand to eye coordination
<span>select the New Slide option from the Insert menu</span>
The best scenario is when a program suffers from frequent
page faults. In the situations when a kernel thread experiences a page fault,
another kernel thread can be switched in; something a single-threaded process
will not be capable of doing. Another best circumstance is when a program has
to wait for other systems events.
