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4 years ago

What’s the answer to these two?!? Thanks LOVE BRAINLYY

Mathematics

2 answers:

Travka [436]4 years ago

5 0

The answer is either 72 using multiplication with 12 or 6 or it is 18 using addition.Not exactly sure but hope it helps a little

serg [7]4 years ago

3 0

<span>The correct answer to ya question is 72.
Hope I was able to help,~kashout kam

</span>

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Identify the class width, class midpoints, and class boundaries for the given frequency distribution.Daily Low Tempurature Frequ

Natali [406]

Answer:

I . class width is 3

ii. Class midpoints are 33,36,39,42,45,48,51.

iii. Class boundaries are: 31.5-34.5, 34.5-37.5, 37.5-40.5, 40.5-43.5, 43.5-46.5, 46.5-49.5, 49.5-52.5

Step-by-step explanation:

I. The class width is the difference between upper class boundary and lower class boundary.

ii. Class midpoints is the summation of upper and lower class limits, divided by 2.

iii. Class boundaries is the subtraction of 0.5 from the lower classe limits and the addition of 0.5 to upper class limits.

8 0

3 years ago

Given parallelogram E F G H with diagonals that intersect at point J comma segment E J is congruent to which segment?

guapka [62]

Answer:

Given: A parallelogram EFGH in which diagonals intersect at point J.

To Find: A segment congruent to EJ.

Solution: In parallelogram EFGH

Point of intersection of Diagonals EG and FH are point J.

As we know diagonals of parallelogram bisect each other.

So, EJ=JG and FJ=JH

∵ Solution is EJ≅ JG

5 0

4 years ago

A decimal that is equivalent to 188/11

nekit [7.7K]

17.09090909... Just divide 188 by 11

8 0

4 years ago

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Three in seven times four on three

IgorC [24]

Answer:

Step-by-step explanation:

So not exactly sure what your asking because of the wording but I got 28. Hope this helps.

7 0

3 years ago

Read 2 more answers

Trig: Which complex number's graph is shown?

Andrei [34K]

ANSWER

$2 \sqrt{2} ( \cos( \frac{7\pi}{4} + i \sin( \frac{7\pi}{4} ) )$

EXPLANATION

The complex number shown has coordinates (2,-2)

$z = 2 - 2i$

The modulus is

$|z| = \sqrt{ {2}^{2} + {( - 2)}^{2} }$

$|z| = \sqrt{ 8} = 2 \sqrt{2}$

The argument is

$\theta= \tan^{ - 1} ( \frac{ - 2}{2} )$

$\theta= \tan^{ - 1} ( -1) = \frac{7\pi}{4}$

The polar form is

$2 \sqrt{2} ( \cos( \frac{7\pi}{4} + i \sin( \frac{7\pi}{4} ) )$

The first option is correct.

3 0

4 years ago