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3 years ago

For what domain intervals is the function y = lx - 11 increasing and/or decreasing?

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:

it will. keep going constant and it won't stop unless it will decrease or increase

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Given the function f(x) = 5(x+4) − 6, solve for the inverse function when x = 19.

meriva

Answer:

5.74

Step-by-step explanation:

fx=5(x+4)-6

f(19)=5(19+4)-6

19f=5(23)-6

19f=115-6

19f=109

f=109÷19

f=5.74 or 19 14/19

7 0

3 years ago

Expand the polynomial and simplify: (4xy− 1 8 y^2)^2

Vinvika [58]

Answer: $4y^{2}(2x-9y)^{2}$

Step-by-step explanation:

We have the following polynomial:

$(4xy-18y^{2})^{2}$

This is a polynomial of the form $(a-b)^{2}=a^{2}-2ab+b^{2}$ . Following this rule to expand it, we have:

$(4xy)^{2}-2(4xy)(18y^{2})+(18y^{2})^{2}$

$16x^{2}y^{2}-144xy^{3}+324y^{4}$

Applying common factor $4y^{2}$ :

$4y^{2}(4x^{2}-36xy+81y^{2})$

Note the polynomial inside the parenthesis is a perfect square trinomial, which can be factored to $(2x-9y)^{2}$ . Hence, the final simplification is:

$4y^{2}(2x-9y)^{2}$

3 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago

HELP PLEASE ASAP 55 POINTS I BEG YOU!!!!!!

Alja [10]

Answer:1 b+1T+1 U=5617b+1 T =9062b+7T+5U = 1758

Step-by-step explanation:

3 0

3 years ago

A right rectangle prism has a length of 5 cm a width of 4 cm and a height of 3 cm the dimensions of the prism are doubled what i

IRISSAK [1]

Answer: 376 cm^2

Step-by-step explanation:

First you would double all the dimensions:

l = 5 cm x 2 = 10 cm

w = 4 cm x 2 = 8 cm

h = 3 cm x 2 = 6 cm

The formula for finding the surface area of a rectangular prism is A=2(wl+hl+hw)

Substitute the values:

A=2(8*10+6*10+6*8)

Solve using PEMDAS:

A=2(80+60+48)

A=2(188)

A=376

Surface area is always in units^2:

376 cm^2

5 0

3 years ago