Answer:
Step-by-step explanation:
1 ) k²-8k = 0
k(k-8)=0
k = 0 or k=8
2) a²+5a=0
a(a+5) = 0
a=0 or a = - 5
3 ) 6n²+5n-25=0
delta = b²-4ac b =5 and a = 6 and c= - 25
delta = 5²-4(6)(-25) = 625 = 25²
n 1 = (-5+25)/12 = 20/12 = 5/3
n 2 = (-5-25)/12 = - 30/12 = -5/2
same method for 4) and 5)
The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows

Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Hence, the value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Read more about equations at:
brainly.com/question/2972832
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Lets just choose the first one, 3 4 and 5. According to the Pythagorean Theorem,
a^2+b^2=c^2
So lets plug in our numbers.
3^2+4^2=c^2
The answer should be 5, but lets make sure.
3*3 = 9
4*4 = 16
9+16=c^2
25 = c^2
Square root both sides so:
5=c
And sure enough 5 is the last number on that list. The order doesn’t matter as long as the value you are trying to find is the c^2.
Answer:
m ≤ -15
Step-by-step explanation:
You can convert m into positive by multiplying -1 on both sides of the equation. This would also result to a -15.
Note that when an unknown variable changes its sign, the symbol becomes the opposite version of itself.
So,
-m ≥ 15
-m(-1) ≥ 15(-1)
m ≤ -15