Assume L || M.<br><br><br> PLEASE HELP!!!

Find the measure of arc DF

givi [52]

Answer:

Step-by-step explanation:

Angle E is one-half the measure of the difference between arc CG and arc DF. Mathematically, that looks like this:

$44=\frac{1}{2}(160-DF)$ and

44(2) = 160 - DF and

88 = 160 - DF and

-72 = -DF so

DF = 72 degrees, second choice down

7 0

3 years ago

Age word problems

SIZIF [17.4K]

36

Explanation: have a little faith in me I don’t want to type it all out thank you for your time :) -sorry if that sounded a little rude

4 0

3 years ago

Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units

Lady_Fox [76]

Answer:

a. the motion is positive in the time intervals: $[0,2)U(6,\infty)$

The motion is negative in the time interval: (2,6)

b. S=7 m

c. distance=71m

Step-by-step explanation:

a. In order to solve part a. of this problem, we must start by determining when the velocity will be positive and when it will be negative. We can do so by setting the velocity equation equal to zero and then testing it for the possible intervals:

$3t^{2}-24t+36=0$

so let's solve this for t:

$3(t^{2}-8t+12)=0$

$t^{2}+8t+12=0$

and now we factor it again:

(t-6)(t-2)=0

so we get the following answers:

t=6 and t=2

so now we can build our possible intervals:

$[0,2) (2,6) (6,\infty)$

and now we test each of the intervals on the given velocity equation, we do this by finding test values we can use to see how the velocity behaves in the whole interval:

[0,2) test value t=1

so:

$v(1)=3(1)^{2}-24(1)+36$

v(1)=15 m/s

we got a positive value so the object moves in the positive direction.

(2,6) test value t=3

so:

$v(1)=3(3)^{2}-24(3)+36$

v(3)=-9 m/s

we got a negative value so the object moves in the negative direction.

$(6,\infty)$ test value t=7

so:

$v(1)=3(7)^{2}-24(7)+36$

v(1)=15 m/s

we got a positive value so the object moves in the positive direction.

the motion is positive in the time intervals: $[0,2)U(6,\infty)$

The motion is negative in the time interval: (2,6)

b) in order to solve part b, we need to take the integral of the velocity function in the given interval, so we get:

$s(t)=\int\limits^7_0 {(3t^{2}-24t+36)} \, dt$

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{7}_{0}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{7}_{0}$

so now we evaluate the integral:

$s=7^{3}-12(7)^{2}+36(7)-(0^{3}-12(0)^{2}+36(0))$

s=7 m

for part c, we need to evaluate the integral for each of the given intervals and add their magnitudes:

[0,2)

s(t)=\int\limits^2_0 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{2}_{0}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{2}_{0}$

so now we evaluate the integral:

$s=2^{3}-12(2)^{2}+36(2)-(0^{3}-12(0)^{2}+36(0))$

s=32 m

(2,6)

s(t)=\int\limits^6_2 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{6}_{2}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{6}_{2}$

so now we evaluate the integral:

$s=6^{3}-12(6)^{2}+36(6)-(2^{3}-12(2)^{2}+36(2))$

s=-32 m

(6,7)

s(t)=\int\limits^7_6 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{7}_{6}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{7}_{6}$

so now we evaluate the integral:

$s=7^{3}-12(7)^{2}+36(7)-(6^{3}-12(6)^{2}+36(6))$

s=7 m

and we now add all the magnitudes:

Distance=32+32+7=71m

7 0

3 years ago

How to write an equation of a line perpendicular to another line?

Nimfa-mama [501]

They would have to have opposite slopes. ex: Y=2x+4 | Y=-1/2x+8 or if you are asking in general you could write. LINE AB | LINE CD

3 0

3 years ago

Simon had 2 cups of jelly he put the jelly in to 1/3 cup jars how many jars of jelly did he make

Hoochie [10]

Answer: 6 jars

Step-by-step explanation:

All you need to do is divide 2 by 1/3. This is the same thing as multiplying 2 by the reciprocal of 1/3 (just flip the fraction) which is 3/1 or 3. Now, just multiply 2 and the reciprocal of 1/3, which we found out was three, and you should should get your answer of 6 jars. Hope this helps!

4 0

3 years ago

Assume L || M. PLEASE HELP!!!