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shepuryov [24]
3 years ago
9

You are choosing between two plans at a health club. Plan A offers an initial membership fee of $75. And you pay $15 per month.

Plan B offers an initial membership fee of $20 and you pay $26 a month. How many months are the two clubs the same price?
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

5 months

Step-by-step explanation:

Let the number of months equalising both plans fee = x

Plan A total fee = 75 + 15x , Plan B total fee = 20 + 26x

Equalise both: 75+15x = 20+26x ; 75-20 = 26x-15x ; 55 = 11x ; x = 55 / 11

x = 5  

Proof : 75 + 15 (5) = 20 + 26 (5) ; LHS 150 = RHS 150

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Assuming that <em>a + 2 = y</em>, the property that was applied to arrived at <em>(a + 2)/3 = y/3</em> is the: division property of equality.

<em><u>Recall:</u></em>

What is done to both sides of an equation will determine what property of equality was applied to the equation.

  • Thus, given the equation:

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(a + 2)/3 = y/3

Observing the equation stated above, we will see that both sides of the equation was divided by three. This makes both sides equal.

Therefore, assuming that <em>a + 2 = y</em>, the property that was applied to arrived at <em>(a + 2)/3 = y/3</em> is the: division property of equality.

Learn more here:

brainly.com/question/13260378

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B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}

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