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Varvara68 [4.7K]
3 years ago
11

Subtract 7/9 from 4 / 9​

Mathematics
2 answers:
poizon [28]3 years ago
6 0
The Answer is 3/9

7-4=3
Oksanka [162]3 years ago
5 0

Answer:

3/9

Step-by-step explanation:

You just substract the numerator :) So, 7-4= 3

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What does a equal in 1/2(a-7)=33?​
Dmitriy789 [7]

To find a, you need to isolate/get the variable "a" by itself in the equation:

\frac{1}{2} (a-7)=33    Multiply the inverse of 1/2, which is 2, to get rid of the fraction

(2)\frac{1}{2}(a-7)=(2)33

a - 7 = 66      Add 7 on both sides to get "a" by itself

a - 7 + 7 = 66 + 7

a = 73

6 0
3 years ago
Stretch your thinking Will you make a new ten to solve this problem? 59 + 17 explain
topjm [15]

Hey there! :D

So you're wondering if you can make a new ten in this problem, right? Well, lets find out! We can simply do<span> 59 + 17 = 59 + 1 + 16 = 60 + 16 = 76. When we did 59 + 1, that is a new ten then we added to 16. So yes, we did make a new ten in this problem. </span>

<span>Hope it helps! ;)</span>

4 0
3 years ago
Read 2 more answers
Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3
lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 72.3, \sigma = 8.9

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 73.9}{8.9}

Z = 1.81

Z = 1.81 has a pvalue of 0.9649

X = 82

Z = \frac{X - \mu}{\sigma}

Z = \frac{82 - 73.9}{8.9}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0
3 years ago
A 150-unit apartment complex is infested with rats. The apartment caretaker checked 9 units and found the following number of ra
MA_775_DIABLO [31]
{2, 5, 3, 1, 0, 3, 7, 2, 2} is the data set. We can find this by finding <span>relative frequency of 3 = 2/9 = 0.22 and then 150 times .22 = 33 units</span>
8 0
3 years ago
Please help me!? Explain why i got this wrong ? how to do it right?
IgorLugansk [536]
Y - y1 = m(x - x1)
slope(m) = -3/7
(5,8)...x1 = 5 and y1 = 8
now we sub
y - 8 = -3/7(x - 5) <===
3 0
3 years ago
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