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Varvara68 [4.7K]
3 years ago
11

Subtract 7/9 from 4 / 9​

Mathematics
2 answers:
poizon [28]3 years ago
6 0
The Answer is 3/9

7-4=3
Oksanka [162]3 years ago
5 0

Answer:

3/9

Step-by-step explanation:

You just substract the numerator :) So, 7-4= 3

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Try It! Class A was given a sunflower with a height of 8 centimeters that grows at a rate of 3 1/2 centimeters per week. Class B
igor_vitrenko [27]

Answer:

8 Weeks

Step-by-step explanation:

First let's collect the given data:

• <u>Class A:</u>

- Starts at 8 cm

- grows at 3.5 cm/week

• <u>Class B:</u>

- Starts at 10cm

- grows at 3.25 cm/week

Class B's plant starts out 2 cm taller and Class A's plant grows 1/4 cm faster. So, to find when these two will be at an equal height, divide 2 cm by 1/4.

2 ÷ 1/4 =

2 × 4/1 =

2 × 4 =

8

It will take 8 weeks for the plants to be at an equal height.

8 0
3 years ago
A special Olympic event has 16 more boys than girls competing. The total number of participants is 1000. How many boys completed
Ray Of Light [21]

x= the number of girls competing

x+16=the number of boys competing

The equation to find the number of boys and girls competing would be:

x+(x+16)=1000

First, combine like terms:

2x+16=1000

Subtract 16 from both sides.

2x=984

Divide both sides by 2:

x=492

We know now that the number of girls competing is 492. To find the number of boys competing, you simply have to add 16 to 492.

492+16=508

There are 508 boys competing and 492 girls competing.

I hope this helps :)

6 0
3 years ago
Olivia is growing roses and keeps track of how much fertilizer (in ounces) she adds to the soil and how many blooms each rose
lina2011 [118]

Answer:

i am in middle school but i know it Yx6

Step-by-step explanation:

7 0
3 years ago
The record low for Florida is 2 degrees below zero Fahrenheit and was set on February 13, 1899. The record high is 109 degrees F
jarptica [38.1K]

Answer:

-2 and 109

Step-by-step explanation:

just put that

4 0
3 years ago
Read 2 more answers
∆ ABC is similar to ∆DEF and their areas are respectively 64cm² and 121cm². If EF = 15.4cm then find BC.​
lyudmila [28]

{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}

★ ∆ ABC is similar to ∆DEF

★ Area of triangle ABC = 64cm²

★ Area of triangle DEF = 121cm²

★ Side EF = 15.4 cm

{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}

★ Side BC

{\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}

Since, ∆ ABC is similar to ∆DEF

[ Whenever two traingles are similar, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. ]

\therefore \tt \boxed{  \tt \dfrac{area( \triangle \: ABC )}{area( \triangle \: DEF)} =  { \bigg(\frac{BC}{EF} \bigg)}^{2}   }

❍ <u>Putting the</u><u> values</u>, [Given by the question]

• Area of triangle ABC = 64cm²

• Area of triangle DEF = 121cm²

• Side EF = 15.4 cm

\implies  \tt  \dfrac{64   \: {cm}^{2} }{12 \:  {cm}^{2} }  =  { \bigg( \dfrac{BC}{15.4 \: cm} \bigg) }^{2}

❍ <u>By solving we get,</u>

\implies  \tt    \sqrt{\dfrac{{64 \: cm}^{2} }{ 121 \: {cm}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \sqrt{\dfrac{{(8 \: cm)}^{2} }{  {(11 \: cm)}^{2} }}   =   \bigg( \dfrac{BC}{15.4 \: cm} \bigg)

\implies  \tt    \dfrac{8 \: cm}{11 \: cm}    =   \dfrac{BC}{15.4 \: cm}

\implies  \tt    \dfrac{8  \: cm \times 15.4 \: cm}{11 \: cm}    =   BC

\implies  \tt    \dfrac{123.2 }{11 } cm   =   BC

\implies  \tt   \purple{  11.2 \:  cm}   =   BC

<u>Hence, BC = 11.2 cm.</u>

{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}

★ Figure in attachment.

\rule{280pt}{2pt}

4 0
3 years ago
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