The prime factors of 6 are 2 and 3. So for a number to be divisible by 6,it must also be divisible by 2 and 3.Therefore,we need to check if a number is even and then check if the sum of the digits is divisible by 3
Answer:
i dont know sorry
Step-by-step explanation:
When you factor you get (x-2)(x-3)=0 then x=2 and x=3
So,
You have to undistribute a common factor in all of the terms.
2a + 2b
There is a 2 in each term.
Undistribute.
2(a + b)
Answer:
what i dont unederstand
Step-by-step explanation: jk its 2343 terms
