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Blababa [14]
3 years ago
9

A(n) = -6 - 4(n -1) find the 4th term in the sequence.

Mathematics
1 answer:
seropon [69]3 years ago
3 0

\bf \begin{array}{ccll} n&term&\stackrel{-6-4(n-1)}{value}\\ ------&------&------\\ 1&A(1)&-6-4(1-1)\\ &&-6-4(0)\\ &&-6\\\\ 2&A(2)&-6-4(2-1)\\ &&-6-4\\ &&-10\\\\ 3&A(3)&-6-4(3-1)\\ &&-6-8\\ &&-14\\\\ 4&A(4)&-6-4(4-1)\\ &&-6-12\\ &&-18 \end{array}

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The graph of f is shown. find and interpret f(45).
Ket [755]

The function represents the number of accidents (f(x)) per 50 million miles driven as a function of the driver's age (x).

f(x)=0.4x^2-36x+1000

f(45) indicates that you have to find the value of f(x) when x=45, to do so replace the equation of the function with the value of x and solve for f(x)

\begin{gathered} f(x)=0.4x^2-36x+1000 \\ f(45)=0.4(45)^2-36\cdot45+1000 \\ f(45)=0.4\cdot2025-1620+1000 \\ f(45)=810-1620+1000 \\ f(45)=190 \end{gathered}

For x=45 years f(x)=190

f(45)=190; This value indicates that 45-year-old drivers had 190 accidents per 50 million miles driven.

8 0
1 year ago
(X,y) —> (x,-y) rule
ch4aika [34]
Can you help me with math
5 0
3 years ago
Change 196% to a whole number
Vesna [10]
196% = 100% + 96%

=100/100 + 96/100

=1 + 96/100 

=1.00 + 0.96

=1.96
8 0
3 years ago
Read 2 more answers
Blood pressure: High blood pressure has been identified as a risk factor for heart attacks and strokes. The proportion of U.S. a
Y_Kistochka [10]

Answer:

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

For this case we know this:

n=37 ,  p=0.2

We can find the standard error like this:

SE = \sqrt{\frac{\hat p (1-\hat p)}{n}}= \sqrt{\frac{0.2*0.8}{37}}= 0.0658

So then our random variable can be described as:

p \sim N(0.2, 0.0658)

Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:

P(p>0.4)

We can use the z score given by:

z = \frac{p -\mu_p}{SE_p}

And using this we got this:

P(p>0.4) = 1-P(z< \frac{0.4-0.2}{0.0658}) = 1-P(z

And we can find this probability using the Ti 84 on this way:

2nd> VARS> DISTR > normalcdf

And the code that we need to use for this case would be:

1-normalcdf(-1000, 3.04; 0;1)

Or equivalently we can use:

1-normalcdf(-1000, 0.4; 0.2;0.0658)

Step-by-step explanation:

We need to check if we can use the normal approximation:

np = 37 *0.2 = 7.4 \geq 5

n(1-p) = 37*0.8 = 29.6\geq 5

We assume independence on each event and a random sampling method so we can conclude that we can use the normal approximation and then ,the population proportion have the following distribution :

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

For this case we know this:

n=37 ,  p=0.2

We can find the standard error like this:

SE = \sqrt{\frac{\hat p (1-\hat p)}{n}}= \sqrt{\frac{0.2*0.8}{37}}= 0.0658

So then our random variable can be described as:

p \sim N(0.2, 0.0658)

Let's suppose that the question on this case is find the probability that the population proportion would be higher than 0.4:

P(p>0.4)

We can use the z score given by:

z = \frac{p -\mu_p}{SE_p}

And using this we got this:

P(p>0.4) = 1-P(z< \frac{0.4-0.2}{0.0658}) = 1-P(z

And we can find this probability using the Ti 84 on this way:

2nd> VARS> DISTR > normalcdf

And the code that we need to use for this case would be:

1-normalcdf(-1000, 3.04; 0;1)

Or equivalently we can use:

1-normalcdf(-1000, 0.4; 0.2;0.0658)

7 0
2 years ago
Helpppppppp meeeee please ASAP
Aleks [24]

Answer:

(9, 13, 22)

Step-by-step explanation:

We can use the triangle inequality theorem to help us solve this problem. We know that the two shortest sides of a traingle added up (their sum) needs to always be greater than the longest side of the triangle. Taking that information, we can figure out that 9+13=22. 22=22, not 22>22. This means that is the right answer, hopefully that helps!

5 0
2 years ago
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