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Irina-Kira [14]
3 years ago
9

6:___=9:12 Find the missing number of ratio

Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

<h2><u><em>8</em></u></h2>

Step-by-step explanation:

6:___=9:12

Find the missing number of ratio

6 : x = 9 : 12

x = 6 * 12 : 9

x = 8

----------------------------

check

6 : 8 = 9 : 12

0.75 = 0.75

the answer is good

Nastasia [14]3 years ago
7 0
8 because - 3 from each side and you get 6 and 8
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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
4 years ago
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sineoko [7]

Answer:

$12

Step-by-step explanation:

8 0
3 years ago
If a card is chosen at random from a pack of 52 playing cards, what is the probability of a Queen or a Club?
bonufazy [111]
The answer is b because you have 4 queens in a deck of cards and 13 clubs in a deck so if you add them you would get 17/52 cards
6 0
3 years ago
HELP PLEASE and show work
larisa86 [58]

Answer:

\boxed{\stackrel{\Large\frown}{PQS}\:= 222°}

Explanation:

Since \overline{PR} is a diameter, arc \stackrel{\Large\frown}{PQR}\:= 180°.

Given that \angle{SUR} = 42° is a subtended central angle by two diameters,

\stackrel{\large\frown}{RS} \:= 42°.

Using the rule of arcs, \stackrel{\Large\frown}{PQR} + \stackrel{\large\frown}{RS} \: = \: \stackrel{\Large\frown}{PQS} →

180° + \: 42° = \: \stackrel{\Large\frown}{PQS}

222° = \: \stackrel{\Large\frown}{PQS}

\stackrel{\Large\frown}{PQS} \: = \: 222°

3 0
3 years ago
Consider a population p of field mice that grows at a rate proportional to the current population, so that dp dt = rp. (note: re
krok68 [10]
This is the concept of differential equations, given that
dp/dt=rp
then:
dp/p=rdt
thus:
ln p=rt+C
p=e^(rt+C)
P=Ke^(rt)
when t=210 days=7 months, p=2k
2k=k×e^(7r)
2=e^(7r)
ln2=7r
r=ln(2)/7
r=0.0990
5 0
3 years ago
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