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3 years ago

Factor out the coeficcent of the variable. 1.) 4h - 3Please explain your anwser

1 answer:

7 0

4n - 3 = 0
+3 +3
--------------
4n = 3

4n = 3
*divide out the 4 from the n and then divide into 3*

n=0.75
I'm pretty sure that is what your looking for, anywho, I hope it helps :)

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Original price: $264.91<br> Markdown: 79%<br> The sale price is $

-BARSIC- [3]

264.91 times .79 is 209.2789
Subtract 209.2789 from 264.91 is 55.6311
The sale price is $55.63

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3 years ago

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!!

Bogdan [553]

Answer:

Step-by-step explanation:

Since it’s asking for numbers between -1 and 8 the equation cannot contain a equal symbol therefore it must be D

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3 years ago

A Statistics class has a test average of 87 with a standard deviation of 2.1. Find the z-score that corresponds to Kate's test s

Leto [7]

Answer:

2.86

Step-by-step explanation:

So I'm pretty sure we don't want the probability, just the zscore

to find the zsore subtract the mean and divide by the standard deviation

(93-87)/2.1= 2.86

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3 years ago

Convert x = 4 to polar form

dezoksy [38]

Answer: r = 4 sec θ

Explanation: Using: x = r cos θ then r cos θ = 4 ⇒ r = 4 cos θ = 4 sec θ

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3 years ago

A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were born

strojnjashka [21]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 335, \pi = \frac{268}{335} = 0.8$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563$

For the percentage:

Multiplying the proportions by 100.

The 99% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0

4 years ago