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2 years ago

List down the currency value of AED to INR from 11th October 2018 to 27 October

Mathematics

1 answer:

lakkis [162]2 years ago

6 0

Thursday 11 October 2018 1 AED = 20.1594 INR

Friday 12 October 2018 1 AED = 20.0615 INR

Saturday 13 October 2018 1 AED = 20.0615 INR

Sunday 14 October 2018 1 AED = 20.0619 INR

Monday 15 October 2018 1 AED = 20.0838 INR

Tuesday 16 October 2018 1 AED = 20.0005 INR

Wednesday 17 October 2018 1 AED = 20.0333 INR

Thursday 18 October 2018 1 AED = 20.016 INR

Friday 19 October 2018 1 AED = 20.0034 INR

Saturday 20 October 2018 1 AED = 20.0034 INR

Sunday 21 October 2018 1 AED = 20.0045 INR

Monday 22 October 2018 1 AED = 20.0549 INR

Tuesday 23 October 2018 1 AED = 19.9376 INR

Wednesday 24 October 2018 1 AED = 19.9364 INR

Thursday 25 October 2018 1 AED = 19.9367 INR

Friday 26 October 2018 1 AED = 19.9077 INR

Saturday 27 October 2018 1 AED = 19.9119 INR

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Elimination <br> 2x - 5y = 8 <br> x - 3y = -1

ruslelena [56]

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You would isolate one of the variables and then plug the expression into the other equation to find the value of one variable. Then you would plug this value into the other equation to determine the value of the remaining variable.

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3 years ago

Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.

fredd [130]

$\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}$

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so the ODE is indeed exact and there is a solution of the form $F(x,y)=C$ . We have

$\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)$

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With $y(1)=2$ , we have

$8+\ln9=C$

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2 years ago

Please help I will give brainliest

Viefleur [7K]

Answer:

option 1 is equivalent to 3^2.3^5

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2 years ago

Read 2 more answers

Pls help branliest if right

Bezzdna [24]

Answer:

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2 years ago

How do I simplify this by combining like terms

pickupchik [31]

You would simplify this expression by adding the coefficients 14 and -5.
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3 years ago