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3 years ago

I need help ASAP!!! (please look at the image and explain how you got the answer, please and thanks)

Mathematics

1 answer:

egoroff_w [7]3 years ago

8 0

Answer:

114

Step-by-step explanation:

so lets call shelf 1 x

shelf 2 is twice size + 18 of shelf 1 so it is 2(x)+18

shelf 3 is 12 less than shelf 1 so x-12

shelf 4 is four more so x+4

Add them all together and it should be 5x+10= 2.5 m or 250 cm

Solve for x using cm

then plug into shelf 2 equation

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A survey measures the motivation, attitudes, and study habits of freshman in college. Freshmans’ scores on this survey range fro

MrRissso [65]

Answer:

Option A) 0.0074

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 110

Sample mean, $\bar{x}$ = 20

Sample size, n = 100

Alpha, α = 0.05

Population standard deviation, σ = 115.35

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 110\\H_A: \mu \neq 110$

We use two-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{115.35 - 110}{\frac{20}{\sqrt{100}} } = 2.675$

Now, we calculate the p-value from the standard normal table.

P-value = 0.0074

Thus, the correct answer is

Option A) 0.0074

5 0

4 years ago

The regular price of a video game is $19.50 The store is having a 40% off sale.

Afina-wow [57]

A. The discount is 7.80 much

B. $11.7

7 0

3 years ago

When it is operating properly, a chemical plant has a daily production rate that is normally distributed with a mean of 885 tons

-BARSIC- [3]

Answer:

The test statistic Z = 1.844 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

Yes he is right

The manager claims that at least 95 % probability that the plant is operating properly

Step-by-step explanation:

Explanation:-

Given data Population mean

μ = 885 tons /day

Given random sample size

n = 60

mean of the sample

x⁻ = 875 tons/day

The standard deviation of the Population

σ = 42 tons/day

Null hypothesis:- H₀: The manager claims that at least 95 % probability that the plant is operating properly

Alternative Hypothesis :H₁: The manager do not claims that at least 95 % probability that the plant is operating properly

Level of significance = 0.05

The test statistic

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{875 -885}{\frac{42}{\sqrt{60} } }$

$Z = \frac{-10}{5.422} = -1.844$

|Z| = |-1.844| = 1.844

The tabulated value

$Z_{\frac{0.05}{2} } = Z_{0.025} = 1.96$

The calculated value Z = 1.844 < 1.96 at 0.05 level of significance

Null hypothesis is accepted

Conclusion:-

The manager claims that at least 95 % probability that the plant is operating properly

8 0

3 years ago

On a piece of paper use a protractor to construct a triangle with angle measures of 40 and 60 what is the measure of the third a

Lina20 [59]

Answer:

80°

Step-by-step explanation:

The angles of a triangle must add up to 180°.

40° + 60° + missing angle = 180°

100° + missing angle = 180°

subtract 100° from both sides

missing angle = 80°

7 0

3 years ago

Wire electrical-discharge machining (WEDM) is a process used to manufacture conductive hard metal components. It uses a continuo

algol13

Answer:

a. no, there are no sufficient data to use

b. assumption b is right

Step-by-step explanation:

a. for the standard deviation to be calculated at 99% confidence, the data needed should be the mean (given), the variate value to be calculated for(not given), the standard deviation(not given), the z value of the normal distribution ( not given),

since there are too many unknown, the data given are not sufficient to calculate.

b. validity of this interval requires that coating layer thickness be at least approximately normally distributed.

6 0

4 years ago