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krok68 [10]
3 years ago
6

Solve the proportion for x. 4/(5x) = 8/9

Mathematics
1 answer:
Verdich [7]3 years ago
5 0
4     8
---   -----
5x    9

5x*2=9
5x=4.5
x=4.5/5 or 0.9
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You want to put some money in a simple interest account it pays 8% interest annually for 2 years you would like to earn 500 doll
Semmy [17]

You deposit some money into a bank account paying 8% simple interest per year. You received $500 in interest after 2 years. How much the deposit (principal) was?


Result


The principal was $3125.


Explanation


Find principal by using the formula I=P⋅i⋅t, where I is interest, P is total principal, i is rate of interest per year, and t is total time in years.


In this example I = $500, i = 8% and t = 2 years, so


IPPP=P⋅i⋅t=Ii⋅t=5000.08⋅2=3125

4 0
3 years ago
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A six-foot person walks from the base of a broadcasting tower directly toward the tip of the shadow cast by the tower. When the
mixas84 [53]
B.  \tan{\alpha}= \frac{h}{122+3}

c.  
\tan{\alpha}=\frac{h}{122+3} = \frac{6}{3}
\\
\\ \frac{h}{125} = 2
\\
\\h=250

4 0
3 years ago
Examine the system of equations.
MrMuchimi

answer:

x =  - 2 \\ y = 2 \\  \\ ( - 2, \: 2)

explanation:

y =  -  \frac{1}{2} x + 1 \\ y = 2x + 6 \\ first \: equation \: add \:  \frac{1}{2} from \: both  \\  sides \\   \\ second \: equation \: subtract \: 2x \: from  \\  both \: sides \\  \\ y +  \frac{1}{2} x = 1 \\ y - 2x = 6 \\ solve \: the \: first \: equation \\  \\ y +  \frac{1}{2} x = 1 \\ subtract \:  \frac{x}{2} from \: both \: sides \\  \\ y =  -  \frac{1}{2} x + 1 \\ substitute \:  -  \frac{x}{2}  + 1 \: for \: y \: in \: the  \\ other \: equation \\  \\  -  \frac{1}{2} x + 1 - 2x = 6 \\ add \:   \frac{1}{2} x \: to \: 2x \\  \\  -  \frac{5}{2} x + 1 = 6 \\ subtract \: 1 \: from \: both \: sides \\  \\  -  \frac{5}{2} x = 5 \\ divide \: both \: sides \: by \:  -  \frac{5}{2}  \\  \\ x =  - 2 \\ substitute \: the \: value \: of \: x \: into \\ an \: equation \\  \\ y =  -  \frac{1}{2} ( - 2) + 1 \\ distribute \\  \\ y = 1 + 1 \\ add  \\  \\ y = 2 \\  \\ ( - 2, \: 2)

7 0
3 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

\text { For cargo plane } \rightarrow \text { distance travelled }=207 \times 5.3 \text { hours }

Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
7 0
3 years ago
Read 2 more answers
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