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3 years ago

Plz help don't get it

Mathematics

1 answer:

alukav5142 [94]3 years ago

6 0

The sum of a number and 11 ⇒ a + 11

The difference of a number and 74 ⇒ a - 74

Eleven added to the product of fourteen and m ⇒ Please solve this on your own.

The quotient of a number and eight take away five is forty-three ⇒ Please solve this on your own.

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3 years ago

A teacher gave her class two exams; 60% of the class passed the second exam, but only 48% of the class passed both exams. What p

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3 0

3 years ago

Simplify Negative 15.6 divided by negative 4.

masha68 [24]

Simplify:

-15.6/-4

( $\frac{-15.6}{-4}$ )

Divide to solve:

You get 3.9

3 0

3 years ago

Integrate the following: ∫<img src="https://tex.z-dn.net/?f=5x%5E4dx" id="TexFormula1" title="5x^4dx" alt="5x^4dx" align="absmid

Fiesta28 [93]

Answer:

A. $x^5+C$

Step-by-step explanation:

This is a great question! The first thing we want to do here is to take the constant out of the expression, in this case 5. Doing so we would receive the following expression -

$5\cdot \int \:x^4dx$

We can then apply the power rule " $\int x^adx=\frac{x^{a+1}}{a+1}$ ", where a = exponent ( in this case 4 ),

$5\cdot \frac{x^{4+1}}{4+1}$

From now onward just simplify the expression as one would normally, and afterward add a constant ( C ) to the solution -

$5\cdot \frac{x^{4+1}}{4+1}\\$ - Add the exponents,

$5\cdot \frac{x^{5}}{5}$ - 5 & 5 cancel each other out,

$x^5$ - And now adding the constant we see that our solution is option a!

3 0

3 years ago

Read 2 more answers

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago