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grandymaker [24]
3 years ago
10

By careful reorganization, a company was able to reduce the cost of operation from $21,840 per month to $17,190 per month. By wh

at percent was the cost of operation reduced?
Mathematics
2 answers:
Ede4ka [16]3 years ago
4 0
Subtract the 17190 from the 21840. you get 4650. 4650 divided by 21840 is 0.21. The percent decrease is 21%
lesya692 [45]3 years ago
4 0

Answer: The cost of operation was reduced by 21.29%.

Step-by-step explanation:

Since we have given that

Cost of operation earlier = $21,840 per month

Cost of operation now = $17,190 per month

Difference between them is given by

$21,840 - $17,190

=$4,650

Percentage by which the cost of operation was reduced is given by

\dfrac{4650}{21840}\times 100\\\\=21.29\%

Hence, the cost of operation was reduced by 21.29%.

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A cyclist can cover a distance of 18 miles in 45 minute. How many miles the cyclist can cover in 6 hours?
kolbaska11 [484]

First, lets find how many miles the cyclist can ride per minute (speed = distance/time).

18/45 = 0.4 miles per minutes

Second, lets find how many miles the cyclist can ride per hour.

0.4 * 60 = 24 miles per hour

Third, lets find how many miles teh cyclist can ride in 6 hours.

24 * 6 = 144 miles in 6 hours

Best of Luck!

3 0
3 years ago
What is the solution to the equation g(x+2) = 27? (1 point)
Anna11 [10]
X= 2.5
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8 0
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What type of correlation is suggested by the scatter plot?
Bas_tet [7]
No correlation is suggested
8 0
3 years ago
Adante begins to evaluate the expression 3 1/3 x 5 1/4 using the steps below
il63 [147K]

Answer:

\frac{35}{2}

Step-by-step explanation:

To solve this problem we need to write the mixed fraction as a fractional number, as follows:

3 1/3 = 3 + \frac{1}{3} = \frac{9+1}{3} = \frac{10}{3}

5 1/4 = 5 + \frac{1}{4} = \frac{20+1}{4} = \frac{21}{4}

Then, evaluating the expression:

\frac{10}{3}×\frac{21}{4} = \frac{210}{12} =  \frac{35}{2}

4 0
3 years ago
Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer
Otrada [13]

Let 2n+1 be the smaller integer. The larger integer is then 2n+3, and we have

(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13

\implies4n^2+2n-12=0

\implies2n^2+n-6=0

\implies(2n-3)(n+2)=0

\implies 2n-3=0\text{ or }n+2=0

\implies n=\dfrac32\text{ or }n=-2

We omit n=-2, since 2(-2)+1=-3 is negative.

Then for n=\dfrac32 we find 2\left(\dfrac32\right)+1=4, but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

3 0
3 years ago
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