Answer:
k = 
Step-by-step explanation:
Fisherman noticed a stretch in the spring = 'b' centimetres
Weight of the fish = a kilograms
If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,
F = kΔx
Where k = spring constant
Δx = stretch in the spring
F = weight applied
F = mg
Here 'm' = mass of the fish
g = gravitational constant
F = a(9.8)
= 9.8a
Δx = b centimetres = 0.01b meters
Therefore, 9.8a = k(0.01b)
k = 
k =
Therefore, spring constant of the spring will be determined by the expression, k =
Answer:
6 = 413 is a not true statement
Step-by-step explanation:
I've attached my work below
Hope it helps, Let me know if you have any questions/concerns !
Have a nice rest of your day :)
Answer:
5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.
The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.
The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).
The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120
(0+2)^3*(0-3)*k = 120
-24k = 120
k = -5
Combining all three conditions, f(x)
= -5(x+2)^3*(x-3)
= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)
= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)
= -5(x^4 + 3x^3 - 6x^2 - 28x -24)
= -5x^4 - 15x^3 + 30x^2 + 140x + 120
Answer:
800 different sets of digits
