Answer: 55 miles per hour
Explanation: that hint is really useful
So if distance = velocity x time
That means 220 = v x 4 hours
To find v, divided 220 by 4
220 divided by 4 = 55
But I have a question:
Is he driving at a constant speed?
and is this 6th grade math? I’m in that grade but you can trust my answer
If im wrong, someone pls correct me
If im right, mark me brainliest pls, im broke, i have no points-
Goodluck!
Answer:
θ = 50 degrees
Step-by-step explanation:
we have sin θ = cos 40°
θ = arcsin ( cos 40°)
and make sure θ is less than 90 and greater than 0
θ = arcsin (0.766044443)
θ = 50 degrees
the top question is the second answer and the second question is also the second answer
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
In the equation given, the Distributive Property is being demonstrated.
