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3 years ago

I thought of a number, added 4 5/7 to it, and got the number 12 times as big as my original what was my number

2 answers:

7 0

Let's call the number you thought of n. Then what the two steps you took can be written as an equation:
$n+4\frac{5}{7}=12n$

Subtract n to get all of your variables to one side:
$4\frac{5}{7}=11n$

At this point, I recommend turning your mixed number into an improper fraction. It will make things easier later on:
$\frac{33}{7}=11n$

Now divide both sides by 11 to get the value of n:
$\frac{3}{7}=n$

lara [203]3 years ago

6 0

Answer:

3/7

Step-by-step explanation:

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A cheese pizza costs $5. Additional toppings cost $1.50 each. Write and graph an equation in two variables that represents the t

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3 years ago

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Step-by-step explanation:

we have

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1 year ago

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2 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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2 years ago